Answer
2.428g
Explanation
Integrated rate law for the first order reaction is
ln[A]t = -kt + ln[A]0
where,
[A]t = concentration of reactant at time t, ?
k = rate constant, 0.0259s-1
[A]0 = concentration of reactant at initial , 17.74g
t = 1.28min = 76.8s
2.303 log[A]t= - kt + 2.303log[A]0
2.303log[A]t = - 0.0259s-1 × 76.8s + 2.303log(17.74g)
2.303log(17.74g/[A]t) = 1.9891
log(17.74g/[A]t) = 0.8637
17.74g/[A]t = 7.306
[A]t = 2.428 g
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