Solution:
When some of the Cu2+ spilled into the compartment with Zn electrode and Zn2+ ions, then the metalic Cu is deposited on Zn electrode and hence, cell potential will be reduced.
Zn +Cu2+ = Zn2+ + Cu (metal)
This Cu metal deposited on Zn electrode and hence minimizes the cell potential.
6. What would be the effect on measured cell potential if some solution in one well...
Do measured cell potentials show any effect of solution concentration on cell potential for the reactions performed in this experiment? For example, would the potential have changed for 0.1 M solutions from standard conditions of 1 M solutions. Yes, the Nernst equation shows potential is dependent on solution concentrations. No, the Nernst equation does not show potential is dependent on solution concentrations. The potential would change if the cathode and anode were mislabeled. Potential is dependent on concentration, but in...
A concentration cell is called such because both the anode and cathode are build from the same components, meaning the standard cell potential is zero volts and the measured cell potential entirely depends on the relative concentration of ions on either side of the electrochemical cell. Consider the following concentration cell Zns)lZn2() (77M)Zn2()(0.50 M)| Znø) 0.50 M) Zn Given that the concentration of zinc ions in the cathode are 0.50 M, what would the concentration of zinc ions need to...
In a copper-zinc voltaic cell, one half-cell consists of a ZnZn
electrode inserted in a solution of zinc sulfate and the other
half-cell consists of a CuCu electrode inserted in a copper sulfate
solution. These two half-cells are separated by a salt bridge.
At the zinc electrode (anode), ZnZn metal undergoes oxidation by
losing two electrons and enters the solution as Zn2+Zn2+ ions. The
oxidation half-cell reaction that takes place at the anode is
Zn(s)→Zn2+(aq)+2e−Zn(s)→Zn2+(aq)+2e−
The CuCu ions undergo reduction...
Prelab Questions: (PL1) For 6 galvanic cell combinations in part 1, write a chemical equation for each cell in a direction that would be spontaneous and the overall cell potential (PL2) For part 2, what is the expected cell potential for that concentration cell? (PL3) Draw a data table you will be filling in during the lab. Include all the measurements that will be made in this lab and qualitative observation if needed. Procedure: Part 1) (1) Obtain copper strip,...
Calculate the theoretical cell potential (E°) of a galvanic cell
under standard conditions made up of copper and magnesium (see Part
II and Table 1 for more information).
PARTIL Creating and Testing Voltaic Cells Introduction and Background for the Voltaic Cells A galvanic cell (sometimes more appropriately called a voltaic cell) consists of two half-cells joined by a salt bridge that allow ions to pass between the two sides in order to maintain electroneutrality. Each half-cell contains the Components of...
EXPERIMENT 1: List the measured potential for Cell 3: Zn|Zn(NO3)2 || Pb(NO3)2|Pb. Based on your observations, do you expect given electrochemical cell to be spontaneous or nonspontaneous? Explain your answer. Pb|Pb(NO3)2||Zn|Zn(NO3)2 EXPERIMENT 1: What would happen to the measured cell potentials if 30 mL solution was used in each half-cell instead of 25 mL? EXPERIMENT 1: Calculate the theoretical standard cell potential for the electrochemical cell that includes the reaction. Mn+Pb2+⟶Mn2++Pb The standard reduction potentials for each half reaction are...
One half-cell in a voltaic cell is constructed from a silver wire electrode in a AgNO3 solution of unknown concentration. The other half-cell consists of a zinc electrode in a 1.9 M solution of Zn(NO3)2. A potential of 1.48 V is measured for this cell. Use this information to calculate the concentration of Ag (aq). E® Zn/Zn2+ = -0.763 V Eº Ag/Ag+ = 0.7994 V Concentration = Submit Answer Try Another Version 6 item attempts remaining
The electrolysis of a concentrated sodium chloride solution would produce? a. sodium metal at the cathode b, sodium metal at the anode c. hydrogen gas at the cathode d. chlorine gas at the cathode A student makes a voltaic cell by filling one small vessel with 1.0 M Cu+2 with a copper electrode and another small vessel with 1.0 M Zn+2 and a zinc electrode but has nothing for a salt bridge. The student then decides that since there is...
What would happen to the measured cell potentials if 30 mL solution was used in each half-cell instead of 25 mL?
What would happen to the measured cell potentials if 30 mL solution was used in each half-cell instead of 25 mL? will rate, thanks!