The position vector for an electron is r Overscript right-arrow EndScripts equals left-parenthesis 4.7 m right-parenthesis i Overscript ? EndScripts minus left-parenthesis 8.5 m right-parenthesis j Overscript ? EndScripts plus left-parenthesis 8.6 m right-parenthesis k Overscript ? EndScripts. Find the magnitude of r Overscript right-arrow EndScripts.
given r = 4.7 i - 8.5 j + 8.6 k
|r| = sqrt(4.7^2+(-8.5)^2 + 8.6^2) = 12.97
hence the magnitude of r = 12.97 m
The position vector for an electron is r Overscript right-arrow EndScripts equals left-parenthesis 4.7 m right-parenthesis...
Here are two vectors: a Overscript right-arrow EndScripts equals left-parenthesis 4.00 m right-parenthesis i Overscript ̂ EndScripts minus left-parenthesis 3.00 m right-parenthesis j Overscript ̂ EndScripts and b Overscript right-arrow EndScripts equals left-parenthesis 6.00 m right-parenthesis i Overscript ̂ EndScripts plus left-parenthesis 8.00 m right-parenthesis j Overscript ̂ EndScripts. What are (a) the magnitude and (b) the angle (counterclockwise from the axis defined by i Overscript ̂ EndScripts) of a Overscript right-arrow EndScripts? What are (c)...
A particle leaves the origin with an initial velocity v Overscript right-arrow EndScripts equals left-parenthesis 8.47 i Overscript ̂ EndScripts right-parenthesis m divided by s and a constant acceleration a Overscript right-arrow EndScripts equals left-parenthesis negative 1.24 i Overscript ̂ EndScripts minus 4.99 j Overscript ̂ EndScripts right-parenthesis m divided by s Superscript 2. When the particle reaches its maximum x coordinate, what are (a) its velocity, (b) its position vector?
The position ModifyingAbove r With right-arrow of a particle moving in an xy plane is given by ModifyingAbove r With right-arrow equals left-parenthesis 3.00 t cubed minus 4.00 t right-parenthesis ModifyingAbove i With caret plus left-parenthesis 5.00 minus 1.00 t Superscript 4 Baseline right-parenthesis ModifyingAbove j With caret with ModifyingAbove r With right-arrow in meters and t in seconds. In unit-vector notation, calculate (a)ModifyingAbove r With right-arrow, (b)v Overscript right-arrow EndScripts, and (c)a Overscript right-arrow EndScripts for t = 3.00...
The position ModifyingAbove r With right-arrow of a particle moving in an xy plane is given by ModifyingAbove r With right-arrow equals left-parenthesis 4 t cubed minus 3 t right-parenthesis ModifyingAbove i With caret plus left-parenthesis 6 minus 2 t Superscript 4 Baseline right-parenthesis ModifyingAbove j With caret with ModifyingAbove r With right-arrow in meters and t in seconds. In unit-vector notation, calculate (a)ModifyingAbove r With right-arrow, (b)v Overscript right-arrow EndScripts, and (c)a Overscript right-arrow EndScripts for t = 2...
A 11 N horizontal force Upper F Overscript right-arrow EndScripts pushes a block weighing 4.7 N against a vertical wall (see the figure). The coefficient of static friction between the wall and the block is 0.71, and the coefficient of kinetic friction is 0.39. Assume that the block is not moving initially. (a) Will the block move? ("yes" or "no") (b) In unit-vector notation Upper F Subscript x Baseline i Overscript ̂ EndScripts plus Upper F Subscript y Baseline j...
Use f prime left parenthesis x right parenthesis equals ModifyingBelow lim With h right arrow 0 StartFraction f left parenthesis x plus h right parenthesis minus f left parenthesis x right parenthesis Over h EndFractionf′(x)=limh→0 f(x+h)−f(x) h to find the derivative at x for the given function. s left parenthesis x right parenthesis equals 2 x plus 6s(x)=2x+6 s prime left parenthesis x right parenthesiss′(x)equals=nothing