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Find all solutions (real or complex) to the following: (a) z² + 2+2 = 0 (Suggestion: quadratic formula) (b) z4 – 16 = 0 (Sugg

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Answer #1

Solution :- (a) z²+2+2=0 = z²z = -b tJb²-4ac 29 bil a=1 (=2 2 = 1 + J 1² - 4x1x2 2x1 2- - t 51-8 a 2- - 1 157 15.12.652) 4 2(6) = 24_16=0 24 = 16 =) 2 - 416 - 2 = -2, +2 Ditterence of square - (-21²- (2) 2 - 4-4 -- 0 Dry

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