Question
given x^2+kx+16=0, find all values that k gives:
a) two real solutions
b) one real solution
c) two complex solutions

7. Given 2? + kx + 16 = 0, find all values of k that give: (a) two real solutions (b) one real solution (c) two complex solu-
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Answer #1

x + kr + 160 (a) two real solehan lor two a4²t but cao real kolution a 6²-4aco Reve 4²+kut 16 =0 (K) ² - 4 x 16x170 K² 64 > oDate : R 2-8 k < = K. (-8,8) to two complex d oo k= (-8,8) de

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