Evaluate I = JJ, že 2x1 da, where D is the rectangular region described by O...
Evaluate I = Jl. 24X/Y dA , where D is the rectangular region described by 0 5x58 In (8), and 16 sys32. (Type an exact answer in simplified form.)
(1) Evaluate S SIS "Jo dzdydi B. Evaluate JJ y dA where D is the region bounded by xay and y = 2 - X.
Evaluate the double integral I = Slo xy dA where D is the triangular region with vertices (0,0), (1,0), (0,6).
4. Evaluate ſfx da, where D is the region in the first quadrant that lies between = 1 and x + y = 2 D
Evaluate the double integral || f(x, y) dA over the region D. JU f(x, y) = 6x + 9y and D = {(x, y)SXS 1, x3 sy s x3 + 1}
y, dA where D is the solid in Octa 2 +--4 and the plane y-i. Evaluate by the cylinder nt I bounded JJD y, dA where D is the solid in Octa 2 +--4 and the plane y-i. Evaluate by the cylinder nt I bounded JJD
Evaluate the integral Sf. 313x + 3y dA where the region R is given by the figure with a = 3 and b = 5. (Assume the curved boundary of the figure is circular with center at the origin.) S IR ŽV3x2 + 3y2 dA = (125sqrt(3)/2)tan^(-1)(3/4)
Evaluate (*V19x2 + 19y2 dA, where D is the shaded region enclosed by the lemniscate curve r = sin(20) in the figure. r2 = sin 20 0.5 os (Use symbolic notation and fractions where needed.) «V19x + 19da = 0 Use cylindrical coordinates to find the volume of the region bounded below by the plane z = 3 and above by the sphere x2 + y2 + 2 = 25. (Use symbolic notation and fractions where needed.) V =
Sketch the given region of integration and evaluate the integral over Rusing polar coordinates Sle**** da: R=(x? #y? 54% R Sketch the given region of integration R. Choose the correct graph below. OA OB Oc OD 55 - A- R (Type an exact answer
4. There is a region O in the plane whose area we wish to compute: JJ, dk dy. It turns out that if we let then in the new coordinates the region Q is described by osu s vand 2 sv s 3. Compute the area of Q. 4. There is a region O in the plane whose area we wish to compute: JJ, dk dy. It turns out that if we let then in the new coordinates the region...