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Evaluate the integral Sf. 313x + 3y dA where the region R is given by the...
Evaluate the integral 1 1 33x2 +3y? da JR where the region R is given by the figure with a = 3 and b = 5. (Assume the curved boundary of the figure is circular with center at the origin.) SUR į V3x2 + 3y2 dA =
(1 point) Math 215 Homework homework7, Problem 2 Evaluate the integral Se *v5x? + 5y da JJR where the region R is given by the figure with a = 5 and c = 4. (Assume the curved boundary of the figure is circular with center at the origin.) SUR À V5x2 + 5y2 dA =
(8 points) Evaluate the surface integral SF. dS where F = (1, 32, 3y) and S is the part of the sphere x2 + y2 + z2 = 4 in the first octant, with orientation toward the origin. SSSF. ds
Write an iterated integral to evaluate the integral || 2?;} dA where R is the triangular region with vertices (18,0), (13,9) and (18,13). R Select all that apply -7 5 162 5 162 18 9 5 2+ - [ ] 22,3 dA= 5 22 43 dy do -7 + R 5 5 S] =2,3 dA – S139 -7 + 5 5 162 -2 + 5 5 22y3 dy do R 13 22,3 dA= -7 5 22 162 5 dy do...
Use polar coordinates to evaluate the integral where R is the region in in the first quadrant enclosed by the circumference x2+y2=4 and the lines x=0 and y=x SUR (60 - 3y)dA Use coordenadas polares para evaluar la integral JR (6x – 3y)dA donde R es la región en en el primer cuadrante encerrada por la circunferencia za + y2 = 4y las rectas r = Oyy=2. 0-8+12V2 O NO ESTÁ LA RESPUESTA O 16 - 12/2 O 12 -...
QUESTION 4 Evaluate the double integral. 6x2 - 3y) da, where R = [(x, y)/05 x 54 and 1sys 3) -304 304 208 -208 QUESTION 5 T F(x, ) dx dy 1. Change the order of integration of S F(x, y) dy dx Click Save and Submit to save and submit. Click Save All Answers to save all ans esc
Use the given transformation to evaluate the integral. 10xy da, where is the region in the first quadrant bounded by the lines y = 1x and y = 3x and the hyperbolas xy - 3 and xy = 3; xu/v, y v
Find integral integral _ 4x + 3y/2x - 3y dA, where R is the parallelogram enclosed by the lines -4x + 3y = 0, - 4x + 3y = 6, 2x - 3y = 1, 2x - 3y = 4 This can be done directly with a tedious computation, or can be done with a change of variables to transform the parallelogram into a rectangle.
Use the given transformation to evaluate the integral. + 16y) da, where R is the parallelogram with vertices (-2, 6), (2,-6), (4,-4), and (0,8); x =
Evaluate the given integral by changing to polar coordinates. ∫∫R(4x − y) dA, where R is the region in the first quadrant enclosed by the circle x2 + y2 = 4 and the lines x = 0 and y = x.