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Change the following bit patterns into base 16, then change the base 16 into base 10.(6...
Base no bit 0 0 Q-2 (25p): Assume that logical addresses are 16-bit long: 3 bits...
Base no bit 0 0 Q-2 (25p): Assume that logical addresses are 16-bit long: 3 bits for segment no and 13 bits for offset. Segment table of the currently running process is given below: a) (5) How many segments can this Segment Present Modify Length process have at maximum? bit 0 00100 0111 0000 0100 0000 1000 0100 b) (15) Convert the following logical 10100 0100 0001 0010 0010 1100 1000 address to physical (real) address. 2 01100 0100 0000...
DO bit 0 1 Q-2 (25p): Assume that logical addresses are 16-bit long: 3 bits for...
DO bit 0 1 Q-2 (25p): Assume that logical addresses are 16-bit long: 3 bits for segment no and 13 bits for offset. Segment table of the currently running process is given below: a) (5) How many segments can this Segment Present Modify process have at maximum? Length bit Base 0 0 0 0100 0111 0000 0100 0000 1000 0100 b) (15) Convert the following logical 1 1 0100 0100 0001 0010 0010 1100 1000 address to physical (real) address...
7. On a machine, an instruction is always 16 bits long, and the re are 16...
7. On a machine, an instruction is always 16 bits long, and the re are 16 registers. (1) Briefly explain the idea of expanding opcode. (5%) (2) Given this scheme of expanding opcode, identify how many three-address instructions, two-address instructions, one-address instructions, and zero- address instructions are supported. (10%) O 0000 xxxx yyyy zzzz 0001 xxxX yyyy ZZZZ 0010 xxxx yyyy zzZZZ 92 3-address SE instructions 0111 xxxx yyyy zzzz 1000 0000 yyyy zzZz 1000 0001 yyyy zzzz 1000 0010...
binary conversions. please help. thank you! Convert the following Binary number to Base 8 4. 1111...
binary conversions. please help. thank you!
Convert the following Binary number to Base 8 4. 1111 1001 0110 0001 1001 0101 1101 1010 1110 0010 0101 Convert the following Base 8 number to binary 5. 200076524, Convert the following Base 8 number to Base 16 6. 1177662231
Convert each of the following 32 IEEE 754 single precision bit patterns to its corresponding decimal...
Convert each of the following 32 IEEE 754 single precision bit patterns to its corresponding decimal value (the bits are separated into groups of 4 to make interpretation easier). Show all of your work and include a few comments as to what you are doing at each step. 1100 0100 1011 1010 0100 1000 0000 0000 a. b. 0100 0101 1110 0010 0110 1101 0000 0000
Convert each of the following 32 IEEE 754 single precision bit patterns to its...
E-Cube algorithm: 1. for source A and destination B, result = A XOR B 2. for...
E-Cube algorithm:
1. for source A and destination B, result = A XOR B
2. for each non-zero bit in the result starting from the least
significant (right most) travel along that dimension
Using the above algorithm give the sequence of hops, node by
node, for the following source and destinations on this
hypercube:
1.0000→1111
2.1111→0000
3. 0101→1010
4. 1100→1000
5. 0001→1000
6. 0010→1111
AQ3 ю. AQ r000 1001 0010 101p.. 001 1011 1100, 1101 0110 Ц10
3. (2 10 20 points) Design a decade counter using a 2-4-2-1 weighted code for decimal...
3. (2 10 20 points) Design a decade counter using a 2-4-2-1 weighted code for decimal digits (see table below) using the following flip-flop types: a. D Flip-flops S-R Flip-flops b. Digit ABCD 0000 1 0001 2 0010 3 0011 4 0100 1011 6 1100 7 1101 8 1110 1111 4. (6 points) Redraw the circuit from problem 3.a. using NAND gates only.
3. (2 10 20 points) Design a decade counter using a 2-4-2-1 weighted code for decimal digits...
Generate the equivalent Sim68 assembly program for the following machine code assuming it originates at address...
Generate the equivalent Sim68 assembly program for the following machine code assuming it originates at address dollar 0000: 1001 0000 0100 0000 0011 0000 0100 0000 0011 0010 0010 1000 0000 0000 0000 1100 0110 0111 0000 0110 0110 1101 1111 1000 1101 0000 0100 0001 0110 0000 1111 0110 0100 1110 0100 0000 0000 0000 0000 0000 0001 0110 1111 0000 1111 1111 1111 1111 1000 0000 0000 0000 0000 0000 0000 0001
2. Decode (get base 10 value of) the following bit patterns using the floating-point format described...
2. Decode (get base 10 value of) the following bit patterns using the floating-point format described below. Show your work and box the final answer. a. 01011010 b. 11001000 00101100 d. 10111001 C. -Bit positions Mantissa Exponent Sign bit
Translate the following lines of assembly into C language. MOV.w #0XF009, R5 ; move source to...
Translate the following lines of assembly into C
language.
MOV.w #0XF009, R5 ; move source to destination assign a hexadecimal value 0x08 to Register R5 ; Roll destination right and send LSB to Carry 1111 0000 0000 1001 -1111 1000 0000 0100 c-1 RRA. W R5 ; Roll destination right through Carry 1111 1000 0000 0100 -1111 1100 0000o 0010 c -o subtract source from destination ; 1111 1100 0000 0010 -0000 0010 1111 1100 RRC.W R5 R5 SWPB.W sign...
Base no bit 0 0 Q-2 (25p): Assume that logical addresses are 16-bit long: 3 bits for segment no and 13 bits for offset. Segment table of the currently running process is given below: a) (5) How many segments can this Segment Present Modify Length process have at maximum? bit 0 00100 0111 0000 0100 0000 1000 0100 b) (15) Convert the following logical 10100 0100 0001 0010 0010 1100 1000 address to physical (real) address. 2 01100 0100 0000...
DO bit 0 1 Q-2 (25p): Assume that logical addresses are 16-bit long: 3 bits for segment no and 13 bits for offset. Segment table of the currently running process is given below: a) (5) How many segments can this Segment Present Modify process have at maximum? Length bit Base 0 0 0 0100 0111 0000 0100 0000 1000 0100 b) (15) Convert the following logical 1 1 0100 0100 0001 0010 0010 1100 1000 address to physical (real) address...
7. On a machine, an instruction is always 16 bits long, and the re are 16 registers. (1) Briefly explain the idea of expanding opcode. (5%) (2) Given this scheme of expanding opcode, identify how many three-address instructions, two-address instructions, one-address instructions, and zero- address instructions are supported. (10%) O 0000 xxxx yyyy zzzz 0001 xxxX yyyy ZZZZ 0010 xxxx yyyy zzZZZ 92 3-address SE instructions 0111 xxxx yyyy zzzz 1000 0000 yyyy zzZz 1000 0001 yyyy zzzz 1000 0010...
binary conversions. please help. thank you!
Convert the following Binary number to Base 8 4. 1111 1001 0110 0001 1001 0101 1101 1010 1110 0010 0101 Convert the following Base 8 number to binary 5. 200076524, Convert the following Base 8 number to Base 16 6. 1177662231
Convert each of the following 32 IEEE 754 single precision bit patterns to its corresponding decimal value (the bits are separated into groups of 4 to make interpretation easier). Show all of your work and include a few comments as to what you are doing at each step. 1100 0100 1011 1010 0100 1000 0000 0000 a. b. 0100 0101 1110 0010 0110 1101 0000 0000
Convert each of the following 32 IEEE 754 single precision bit patterns to its...
E-Cube algorithm:
1. for source A and destination B, result = A XOR B
2. for each non-zero bit in the result starting from the least
significant (right most) travel along that dimension
Using the above algorithm give the sequence of hops, node by
node, for the following source and destinations on this
hypercube:
1.0000→1111
2.1111→0000
3. 0101→1010
4. 1100→1000
5. 0001→1000
6. 0010→1111
AQ3 ю. AQ r000 1001 0010 101p.. 001 1011 1100, 1101 0110 Ц10
3. (2 10 20 points) Design a decade counter using a 2-4-2-1 weighted code for decimal digits (see table below) using the following flip-flop types: a. D Flip-flops S-R Flip-flops b. Digit ABCD 0000 1 0001 2 0010 3 0011 4 0100 1011 6 1100 7 1101 8 1110 1111 4. (6 points) Redraw the circuit from problem 3.a. using NAND gates only.
3. (2 10 20 points) Design a decade counter using a 2-4-2-1 weighted code for decimal digits...
Generate the equivalent Sim68 assembly program for the following machine code assuming it originates at address dollar 0000: 1001 0000 0100 0000 0011 0000 0100 0000 0011 0010 0010 1000 0000 0000 0000 1100 0110 0111 0000 0110 0110 1101 1111 1000 1101 0000 0100 0001 0110 0000 1111 0110 0100 1110 0100 0000 0000 0000 0000 0000 0001 0110 1111 0000 1111 1111 1111 1111 1000 0000 0000 0000 0000 0000 0000 0001
2. Decode (get base 10 value of) the following bit patterns using the floating-point format described below. Show your work and box the final answer. a. 01011010 b. 11001000 00101100 d. 10111001 C. -Bit positions Mantissa Exponent Sign bit
Translate the following lines of assembly into C
language.
MOV.w #0XF009, R5 ; move source to destination assign a hexadecimal value 0x08 to Register R5 ; Roll destination right and send LSB to Carry 1111 0000 0000 1001 -1111 1000 0000 0100 c-1 RRA. W R5 ; Roll destination right through Carry 1111 1000 0000 0100 -1111 1100 0000o 0010 c -o subtract source from destination ; 1111 1100 0000 0010 -0000 0010 1111 1100 RRC.W R5 R5 SWPB.W sign...
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