Consider using CSMA/CD for the channel access protocol on a 10 Mbps Ethernet. Assume NODE X...
Consider using CSMA/CD for the channel access protocol on a 10 Mbps Ethernet. Assume NODE X has encountered 5 collisions for the same frame:
a) What is the probability that this node chooses K=6 after the 4th collision?
b) If K=6 is the random value chosen, how many seconds would the node delay before sensing the channel again?
Homework Answers
a)What is the probability that this node chooses K=6 after the 4th collision?
The probability that a node will choose k=6 after the 4th collision in CSMA/CD is:
25 = 32
p = 1/32
p = 0.03125
p = 0.03125 * 100
p = 3.125%
b) If K=6 is the random value chosen, how many seconds would the node delay before sensing the channel again?
The result of k = 6 corresponds to what delay in seconds on a 10
Mbps Ethernet:
Delay = K * 512 bit times and k = 6
Delay = 6* 512 = 3,072 bit times
3,072bit times/10 mbps=3.072 *10-4 sec.
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