![counting Sort(A[1 ...n]): // assume each A[i] € {1,2,...,k} 1: for v :=1 to k: 2: count[v] := 0 3: for i:=1 to n: 4: count[A[](http://img.homeworklib.com/questions/3459b080-5c26-11ec-8588-ddf6a3f3ca15.png?x-oss-process=image/resize,w_560)
In terms of n, what is the worst-case running time of countingSort on an input array of n letters from the alphabet (so k = 26, and n is arbitrary)?
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The worst-case running time of countingSort is = O(n) because ultimately the inner loop will execute n times and k being a constant does not impact the time complexity.
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In terms of n, what is the worst-case running time of
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