Question

(a) Determine the moment of inertia of the cross-sectional area of the beam about the x- axis and y-axis. (6) Using the parallel axis theorem, determine the moment of inertia of the cross- sectional area about the x'-axis and y'-axis YOU MUST USE THE TABLE PROVIDED FOR (a) ABOVE. 150 mm -- 150 mm 20 mm 200 mm 20 mm 200 mm 20 mm To calculate Ix To calculate ly Section A (mm) Ix (mm) dy (mm) A(dy) (mm) Iy (mm) dx (mm) Adx)2 (mm) # 1 2 3 Σ Ix-axis ly-axis

Also for part b, use parallel axis theorem to calculate x prime and y prime axis.

Answer 1

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- bd3 150mm 150mm 20mm 200mm 390mm C 200mm 20mm 3 20 mm 11 lomm To cakulate IX To colctate Iy Section / A (mm? Ix (mm) dy (m Aldyr Iy (mmu) dx (1) Adxt m4 390 300x20 300x 203 6000 12 = 200000 12 9x105 7200X 150 2 12 390x600 204 3003 150 2340000 450106 7200x 200 360x 20° 15D 1440000 240000 boooxio 20x3003 ISO 20000 12 ustiot (3840000 90240000 360X20 20X360 200 12 7200 777600001 300x20 300x203 10 6000 12 losrior 800x 150 19xros 78160000 288470" E 19200

Ix= 7816 0000+ 3840000 Ix= 82.000000 B 4 Iy= 90240000 + 2880000 Iy = 93120000 mm 4

ny 150 mm ise mm 20mm 20 mm 190mm 2 20mm 200mm 190mm zomat 3) To Caltalate IX To calculate Iy Section Almm) Ix (mm4) dy dy Ally? I Y (mmt) dx (mm) Aldu? (mm) (mmy) mm 4 1 |300x20 300x203 190 6ooox 190 20x300² 6000 12 o 0 12 1140000 200000 45 000000 2 0 1360x20/ 20x 3603 12 7200 7760000 360x200 12 0 240000 بیا 190 6000x190 20x 3003 o 300220 300x20 12 6000 200000 12 1140000 45 000000 7816 0000 2280000 90240000 sy= - 90240000 ommy Ix = 78160000 + 2280000 Ix = 80440000 mm 4