Question

(1 point) NOTE: When using interval notation in WebWork, remember that: You use 'INF' for oo and '-INF' for -0. And use 'U' for the union symbol. Enter DNE if an answer does not exist. f(x) = -1.5x² – 5x – 2 a) Determine the intervals on which f is concave up and concave down. f is concave up on: f is concave down on: b) Based on your answer to part (a), determine the inflection points of f. Each point should be entered as an ordered pair (that is, in the form (x, y)). (Separate multiple answers by commas.) c) Find the critical numbers of f and use the Second Derivative Test, when possible, to determine the relative extrema. List only the x-coordinates. Relative maxima at: (Separate multiple answers by commas.) Relative minima at: (Separate multiple answers by commas.)

Answer 1

Page No. Date. f(x) = -1.5x²-sx-2 f'(20) = - 3X-5 10 = 23-5/3 t'l(x)2-3 to 7 KO fal + fulani Hence fis concave up on uy جای IDN f is concave down on (-00 - - - 1 1 - 7 100) ub f!lcx) = -3 which is never Hence zero inflection point IONE ci 'f"(-sho Hence Relative maxima at -5 Relative minima LONE]