Question

hey please answer in python 3

In this exercise, you will build a program to process files containing paragraphs. The aim of the program is to simply count the number of words and compute their length. The file, however, may contain numbers (eg. "2018") and contains punctuation that should be ignored. There are two data files that you will use to test your program: shortpar.txt and cassini.txt. (1) Prompt the user to enter the name of a file. Store the text in a string and output the name of the file. (4 pts) You should prompt the user for the name of the file: Enter name of file: shortpar.txt File to be processed is: shortpar.txt (2) Now create the program to read the lines of the file, split each line into words, count the words and total their length. You should skip any numbers that are in the file and strip any punctuation from the words. Consider the following characters as punctuation, . !\" ( ). Some of the words in the files may contain apostrophes) but ignore them for this part of the exercise. For example, "NASA's" would be counted as a single word of length 6. You should print out the number of words and their average length. (8 pts). For the file shortpar.txt, the output would be: Enter name of file: shortpar.txt File to be processed is: shortpar.txt The number of words is: 9 The average length of a word is: 4.33 For the file cassini.txt, the output would be: Enter name of file: cassini.txt File to be processed is: cassini.txt The number of words is: 231 The average length of a word is: 5.37 Note: the above examples are shown for you to compare your code through the development process. The actual tests on submission assume you have completed all three tasks, including the following task (3).

This is the test for these questions. it has to be exactly the same as the Expected output.

notice my code is very close to getting it but im always off by 0.01 or 0.02.

Thank you for the help!

Answer 1

Below is the python3 code for mentione problem statement:

You can comment and uncomment below line in the code for implementing with or without apsotrophe.

word = remove_apos(word)

def remove_apos(word_string):
    # remove apostrophe in the word
    word_string = word_string.replace("'", "")

    return word_string

if __name__ == '__main__':
    # user input
    print("Enter name of file : ")
    file_name = input()
    print("File to be processed is : ", file_name)
    # open file
    open_file = open(file_name)
    file_contents = open_file.read()
    # ignore following symbols if exits in file because these are not considerable for word.
    # ignore_char = '''!()-;:'",.?_~1234567890'''
    ignore_char = '!()-;:",.?_~1234567890'
    words_counter = 0 # Count of words
    total_counter = 0 # Sum of lengths of all the words
    for charracter in ignore_char:
        file_contents = file_contents.replace(charracter, '')
    # spliting the file contents in the words
    for word in file_contents.split():

        # comment or uncomment the below line as per with or without apostrophe implementation
        word = remove_apos(word)
        print(word)
        words_counter = words_counter + 1
        total_counter = total_counter + len(word)
    avg_word_len = total_counter / words_counter
    print("The number of words is : ", words_counter)
    print("The average length of a word is : ", "{:.5f}".format(avg_word_len))

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Please find the screenshots of code and output.

demo.py shortpar.txt cassini.txt 1 2 3 4 5 6 7 8 if 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 def remove_apos (word_string): # remove apostrophe in the word word_string = word_string.replace("'", "") return word_string name _main__': # user input print("Enter name of file :") file_name = input() print("File to be processed is : ", file_name) # open file open_file = open(file_name) file contents = open_file.read() # ignore following symbols if exits in file because these are not considerable for word. # ignore_char = "!!(-;:'",.?_-1234567890 ignore_char = '!(-;:",.7_-1234567890 words_counter = 0 # Count of words total_counter = 0 # Sum of lengths of all the words for charracter in ignore_char: file_contents = file contents.replace(charracter, '') # spliting the file contents in the words for word in file_contents.split(): # comment or uncomment the below line as per with or without apostrophe implementation word = remove_apos (word) print (word) words_counter = words_counter + 1 total counter = total counter + len(word) avg_word_Ten = total_counter / words_counter print("The number of words is : ", words_counter) print("The average length of a word is : ", "{:.5f}".format(avg_word_len))

1 2 demo.py shortpar.txt x cassini.txt n (I'm for I am) or because the letter no longer represented a sound (lov'd for loved). Run: AN 10 х demo (4) demo (3) /home/deepak/anaconda3/envs/py3/bin/python /home/deepak/work_place/workspace Enter name of file : cassini.txt File to be processed is : cassini.txt n I'm for I am or because the letter no longer represented a sound lov'd for loved The number of words is : 17 The average length of a word is : 3.88235 Process finished with exit code o

1 2. demo.py shortpar.txt cassini.txt n (I'm for I am) or because the letter no longer represented a sound (lov'd for loved). Typo: In word 'lov'd' more... (Ctrl+F1) Run: demo (4) demo (3) X /home/deepak/anaconda3/envs/py3/bin/python /home/deepak/work_place/workspaces/pyCha Enter name of file : cassini.txt File to be processed is : cassini.txt 9. X TII Im for Ι am or because the letter no longer represented a sound lovd for loved The number of words is : 17 The average length of a word is : 3.76471 Process finished with exit code o

1 2 3 demo.py shortpar.txt cassini.txt x (as in the contraction of do not to don't). (as in the eagle's feathers, or in one month's time). characters (e.g. p's and q's). I Run: 1 AN EI X demo (3) demo (3) Shortpar.txt File to be processed is : shortpar.txt as in the contraction of do not to don't as in the eagle's feathers or in one month's time characters eg p's and q's The number of words is : 24 The average length of a word is : 3.87500 : Process finished with exit code o

1 2 3 4 demo.py shortpar.txt cassini.txt x (as in the contraction of do not to don't). (as in the eagle's feathers, or in one month's time). characters (e.g. p's and q's). Run: A 1 demo (3) demo (3) shortpar.txt File to be processed is : shortpar.txt as in the contraction of do not to dont as in BOX III the eagles feathers or in one months time characters eg ps and qs The number of words is : 24 The average length of a word is : 3.66667 Process finished with exit code o