Question

A loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius r = 0.15 m. The normal to the plane of the loop is parallel to a constant magnetic field (ϕ = 0°) of magnitude 0.85 T. What is the change ΔΦ in the magnetic flux that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution?

Answer 1

given data is radius r=0.15m,magnitic field B=0.85T, $\theta$ 1=0⁰, $\theta$ 2=180⁰(f0r half revolution)

change in magnetic flux ΔΦ =AB(cos $\theta$ 1-cos $\theta$ 2)

here A= $\pi$ r²/2=3.14*(0.15)²/2

  ΔΦ=(3.14*(0.15)²/2)*0.85(cos0⁰-cos180⁰)=0.06 weber