Question

Part A Four equal charges Q are at the corners of a square of side a. Find an expression for the magnitude of the force on each charge. Express your answer in terms of variables Q, a, and the Coulomb's constant k. O ALO xºx Vo vx o x ? x10 Submit Previous Answers Request Answer

Answer 1

a. Each Cornens • considen a Contains caual square of side change Q. - 9_ 86 AQ ho AB= BCCD - DA - a let's consider the change a placed at point B. The forces acting on change at B is given below. 0 force acting on change at B due to change at A. use coulomb's low Fn = into a =k Q2 - o (coulomb constant, 476 ② Similanly force acting on change at B due to the change at t is given by 1. Fe = 16 e le a 4716 (BC) Ek my @ ② fonce acting on change at B due to change at D. Here point o is at diagonal of paint B. .. So, BD = VAD? + ABL a ſata? = ma

292 Fo = K ale ked - © Call Nature of all the charges are positive. so nature of all the forces also are repulsive. (see figure) o= 450 so net force at Point B is Fret = FA losuso + f + fc cos 45o - ře fa + tu fc + Fo use enn 0, 0 a ③ - - + et la Finet - Kel + + k - Keep Car t here Ka [ 12+] = Kombe ( ~ 1.9 KQ² They the all changes are same. so magnitude of force on each change is F F = 1.9 key (Al = = 1.9