In python:
Not sure how to do a Collatz function.
Remember the Collatz function? If x is odd, then collatz(x) = 3
⋅ x + 1 but if x is even
then collatz(x) = x/2. (remember to use // to divide by 2)
Start by writing a Collatz() function that returns the value for a
given input. Test
this function for all numbers from 1 to 10.
Next write a Collatz2() method. This method should take in a single
number and
repeatedly use the Collatz() function printing out the result while
the number is not
one.
For example:
If I say Collatz2(5), Then the output should be :
5
16
8
4
2
1
If I say Collatz2(12), Then the output should be :
12
6
3
10
5
16
8
4
2
1
Once you know it is working, run your method on the number n =
27 and see how long
it takes to get to 1.
here is the python code in python 3:
===============================================================
Program:
===============================================================
def Collartz(n):
print(n)
while n != 1:
if n%2 != 0:
n = 3*n+1
print(n)
if n%2 == 0:
n = n//2
print(n)
n = int(input("Enter n: "))
Collartz(n)
==============================================================
Screen shot of the code..
===============================================================
Output:
Enter n: 27
27
82
41
124
62
31
94
47
142
71
214
107
322
161
484
242
121
364
182
91
274
137
412
206
103
310
155
466
233
700
350
175
526
263
790
395
1186
593
1780
890
445
1336
668
334
167
502
251
754
377
1132
566
283
850
425
1276
638
319
958
479
1438
719
2158
1079
3238
1619
4858
2429
7288
3644
1822
911
2734
1367
4102
2051
6154
3077
9232
4616
2308
1154
577
1732
866
433
1300
650
325
976
488
244
122
61
184
92
46
23
70
35
106
53
160
80
40
20
10
5
16
8
4
2
1
================================================================
Kindly Check and Verify Thanks..!!!
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