Question

Two objects undergo an elastic collision. Object 1

0 0
Add a comment Improve this question Transcribed image text
Answer #1

given kinetic energy of the object 1 is 51J then we know that kinetic energy is

a)

K.E=0.5mv^2

then velocity of the object 1 is

V1=sqrt((2*K.E)/m1)

=sqrt((2*51)/2.75)

=6.09m/s

b)

By the conservation of energy

K.E of initial system is equal to the final kinetic energy of the system

then kinetic energy of the cart system after the collision is equal to the 51J

c)

for this by the consertation of the momentum

momentum before the collision is equal to the momentum after the collision\

then initial momentum is

M1U1+M2U2

=2.75*6.09+2.6*0

=16.74kgm/s

then final momentum is equal to the 16.74kgm/s

Add a comment
Know the answer?
Add Answer to:
Two objects undergo an elastic collision. Object 1 has a mass of 2.75 kg and object...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Object A has mass mA = 9 kg and initial momentum PA = < 15,-8,0 >...

    Object A has mass mA = 9 kg and initial momentum PA = < 15,-8,0 > kgm/s, just before it strikes object B, which has mass mg = 12 kg. Just before the collision object B has initial momentum 8,1 = < 4,7,0 > kg. m/s. Consider a system consisting of both objects A and B. What is the total initial momentum of this system, just before the collision? sysj = (19,-1,0) kg.m/s The forces that A and B exert...

  • 5. [1pt] Consider a perfectly elastic collision between two objects of equal mass. Object 1 is...

    5. [1pt] Consider a perfectly elastic collision between two objects of equal mass. Object 1 is initially moving with a velocity v = 3.07 m/s while object 2 is at rest. What are the final velocities after the collision? Enter the final velocity of object 1 first. Correct, computer gets: 0.002+00 m/s, 3.07e+00 m/s 6. [1pt] If the objects have masses m = 2.37 kg and m2 = 4.94 kg, what are the final velocities of the objects after the...

  • One object is moving and one object is at rest. The two objects then collide in...

    One object is moving and one object is at rest. The two objects then collide in a dimensional, completely inelastic collision. So the two objects stick together after the collision and move off with a common velocity. Momentum of the two-object system is conserved. The masses of the two objects are 5.00 kg and 8.50 kg, respectively. The speed of the moving object masses 5.00 kg before the collision is 22.5 m/sec. Find the final speed of the two-object system...

  • Two objects are on a collision course. Object #1 has a mass of 12.4 kg and...

    Two objects are on a collision course. Object #1 has a mass of 12.4 kg and an initial velocity of of 22.6 m/s i. If the system is isolated and the objects stick together upon colliding, what is the final velocity of the masses? Let positive answers be (+i) and negative answers be (-i) regarding directions. Object #2 has a mass of 5.0 kg and an initial velocity of -6.3 m/s i.

  • and explain in detail please. Thankyou! 1. In a perfectly ELASTIC collision between two perfectly rigid...

    and explain in detail please. Thankyou! 1. In a perfectly ELASTIC collision between two perfectly rigid objects A) the momentum of each object is conserved B) the kinetic energy of each object is conserved C) the momentum of the system is conserved but the kinetic energy of the system is not conserved D) both the momentum and the kinetic energy of the system are conserved

  • Collision Problem Elastic and Inelastic: Two carts are on a frictionless surface as depicted below. 5...

    Collision Problem Elastic and Inelastic: Two carts are on a frictionless surface as depicted below. 5 m/s 20 kg 10 kg Frictionless surface Part 1. What is the common velocity just after impact if the two stick together, an inelastic collision? Give your answer to 3 significant digits. m/s Part 2. How much Kinetic energy is lost? Give your answer to 3 significant digits. J Part 3. If instead the collision is elastic, what is the velocity of the 10...

  • 14) (Conservation of linear momentum) An air cart of mass m=1 kg and speed vo-Im's moves...

    14) (Conservation of linear momentum) An air cart of mass m=1 kg and speed vo-Im's moves toward second identical air cart that is at rest. When the carts collide, they stick together and move as one a) Using the conservation of linear momentum, calculate the velocity ve when the carts stick together (this is also the velocity of the center of mass after collision). b) Calculate the kinetic energy before and after collision. Is the collision elastic Without any calculation,...

  • A 0.10 kg cart (cart 1) moves with a speed of 0.40 m/s on a frictionless...

    A 0.10 kg cart (cart 1) moves with a speed of 0.40 m/s on a frictionless air track and collides with a stationary cart (cart 2) whose mass is 0.30 kg. The two carts stick together after the collision. put 0 m/s for the velocity of (cart 2) What is given? What is the formula for momentum? Is momentum conserved in this collision? Is kinetic energy conserved in this collision? What is the initial momentum of cart 1? What is...

  • 16. In a perfectly elastic collision Kinetic Energy is conserved for the system. (Remember that elastic...

    16. In a perfectly elastic collision Kinetic Energy is conserved for the system. (Remember that elastic collisions are ones where the objects bounce off of each other and don't stick.) On an air hockey table two identical pucks collide. Initially one is at rest and the other is moving with a speed of v. (Hint: How can the concept of momentum help with this problem?) a. What is the speed of each puck after the collision in terms of the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT