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A loan of $450,000 is amortized over 30 years with payments at the end of each...

A loan of $450,000 is amortized over 30 years with payments at the end of each month and an interest rate of 6.3%, compounded monthly.

Use Excel to create an amortization table showing, for each of the 360 payments, the beginning balance, the interest owed, the principal, the payment amount, and the ending balance.

a) Find the amount of each payment. $  
b) Find the total amount of interest paid during the first 15 payments. $  

Suppose that payment number 6 is skipped and the interest owed for month 6 is added to the balance. Payments then resume as usual for the remainder of the 30 years.
c) Find the balance owing at the end of month 6. $  
d) Find the balance remaining after the 360th payment. $  

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Due to character limit I am attaching the images for amortization schedule.Amortizalion Schedule Psid Beainrina Amount Paid Interest Oved Principal paic Ending 450,214.5 The balane owing s the end cf77 52 61 00 70 67 32 42 17 14 32 70 27 0 8 9 5 3 65 07 56 09 6 2 8 8 SI 40 82 16 41 54 55 41 69 08 97 61 99 Dai-58 24 92 60 390 39 55 37 81 87 53 78 58 93 80 06 40 19 42 07 53 31 43 87 61 63 91 44 19 14 28 57 01 58 24 99 80 65 51 38 23 03 400 400 400Amortization If 76 42 96 38 64 73 63 31 75 34 84 43 70 61 30 02 30 12 44 26 53 25 38 90 79 02 57 41 52 88 45 22 24 44 73 09 466 96 17 26 21 98 56 91 01 82 33 50 30 72 71 25 31 87 89 35 21 45 04 94 13 58 25 17 34 62 98 37 78 17 51 77 91 90 72 32 se es68 76 53 96 01 65 85 57 78 44 53 99 81 35 36 03 90 34 13 41 77 15 53 86 IST 009 201 6 Jes 8 4 4 7 6 3 007 rea ASA 199 9 6 2 1

PMT= PV*i
1-(1+i)^-n
PV= Loan amount 450,000.00
n= no. of payments          360.00
i 6.3%/12 0.00525
PMT= 450000*0.00525
1-(1+0.00525)^-360
PMT= 2362.5
1-(1.00525)^-360
PMT= 2362.5
1-(1.00525)^-360
PMT= 2362.5
1-0.151820550212591
PMT= 2362.5
0.84817945
PMT= 2785.377553
PMT=              2,785.38 round to 2 decimal places
Interest paid during first 15 months:
Sum of interest owed from the amortization table period 1 to 15:$ 35,199.
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