Question

(5) The numbers 1,2,3,4,5, and 6 are written on slips of paper, and 2 slips are drawn at random one at a time without replacement. Find the probabilities of (a) The sum of the outcomes is 8 (b) The first number is 3 or the sum is 8.

Answer 1

It is given that the humbers 1, 2, 3, 4, 5, 6 are written on slips of paper and a slip are drawn at random without replace ment so total no of possible outcome will be (v.2) (1.3) 7.4.) (.5) (1, 6), (2419) & 3), (2,4) (275); (2,6), B. 1) ,3, 2), (3,99 (315), (3;6), (4.1), (4,2), (973), 410) (406) (sud), 52, 513) 69,9) 5.6) (671) 662)(63) 6.41,6 . Te 15)= 30 Let us define an event A such as A Sum of outcome {(2,6), (5), (6,3), (6, 27 } de ha) 4 WA) q so PAD his) 30 HP(A) = 0; 1333 a 3 2

Sth(B) n(s) tine let us define two event LL such A:{ sum is 87 A : {&S) 3), 6:2),(366)} Alq and The ist in z no. 1933 B (3,0; ,2), (15) 2,4)_,8,1) hB25 Soo how (AN BE te ne An B) 1 pt the Ist hoti 3-0 süm is 8) P( A OF B) PC AU BO P(A) E P (B) LAMB). ntan B) his) nis #5 30 30 30 £3,5)}

475-1 6 130 1 / PLAUB) = RAUB) 0:2.6697 Here it is given that & cni-a² = 40 c=1 from ginen question at M clear that ng and we know that simple Standard deyahan 3 (niaj? ht ²ni? 911 5 xo 2:23.67