Question

v(m/s) \ R s (m) (2,0) (3,0)

Velocity versus displacement curve of a particle moving in a straight line is shown in the figure. From a point P, a line PQ is drawn perpendicular to displacement axis and line PR is drawn normal to the curve at P. The magnitude of acceleration of particle at point P is

options:

a)1 m/s^2
b) 3 m/s^2
c)2 m/s^2
d) 2.5 m/s^2

Answer 1

We have been given where sides are given a sight angle A as shown in fig. V o Se, we know the length SPA, 2m (30) 'simy So applying distance formula, Paz Je-nteryeye 12): -2)2 + (0-403) 24-12-27 : (or you y=2m We got the point es, 12,2)-> P Now, Osir transforming v=42+2as 19+4) = 293 vou gymne te yaxis velocity meni slopes o2a, constene: - Now Scope of arc - Slage of normal V- vou La 2 =) a=18(w-u). [ Now, I we have been given voordinate IL Phlength = 2, Vizmis) a: 2-4. I Now initial velocity acch must be less thanezom tone has not been giver Si Ansies 1a) Imist