Question

5. A rigid well-insulated container holds 1 kg of dry saturated steam at P = 5 MPa. At some point in time, a tiny crack develops in the uppermost region of the container. Through this crack, some of the H2O escapes slowly into the atmosphere until the pressure inside the container falls to P2 = 1.5 MPa. This leakage process is slow enough so that at any instant the H2O inventory inside the container is in a state of equilibrium. Any liquid that forms during this process accumulates at the bottom of the container, whereas the escaping H2O is always in the gaseous phase. a. Calculate the vapor quality at the final equilibrium state (2). Note that between 5 MPa and 1.5 MPa, the specific enthalpy of dry saturated steam is practically constant, h, 2800 kJ/kg. b. Calculate the ratio of the volumes occupied by vapor and liquid in the final state (2).

A rigid well insulated container holds 1 kg of dry air at P1= 5 MPa.

Answer 1

no at P = 5 MPa ) dry saturated steam . - , с 20 из кар Si = sģi - 5.974 Regungok New by using equilibrium of system at P2 = 1.sonal 7 Si = S2 = Sf2 + H2 SfJ2 s) 59.974_= 2:314 + 2*4.127 =)() 12 = 0.8877 quality at state (2) Ve + Vv + Vv 0.867 x= my - met my 1 X ₂ = V * 0.887 = Vetve 3 7 867 a) V = 0.127 bler | Viv - 7877 S V = Vol. occupied by q Napour Vo = Volume ocetepied by liquid Ratio of volumes occupied by Vapoan & liquid y = 7 87 Ay