Solution:
Largest 8 bit number is eight 1s i.e. 11111111.
Now 11111111 is 2^0 * 1 + 2^1 * 1 + 2^2 * 1 + 2^3 * 1 + 2^4 * 1 + 2^5 * 1 + 2^6 * 1 + 2^7 * 1 = 1 + 2 + 4 + 8 + 16 + 32 + 64 + 128 = 255.
Note: To convert binary to decimal we multiply the bit value with 2 raised to the power (where power is 0 for bit at extreme right and keeps incrementing by 1 moving towards left).
Therefore, the answer is 255.
The correct option is Option a (255).
What is the largest number that can be represented using eight bits? Select one: a. 255...
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