The largest positive number that can be represented with n bits in 2s complement representation is 2N−1 − 1.
with 12 bits the largest number would be 2^11 - 1 = 2047
so 2047 in hexadecimal 7FF
The answer is 0x7FF
ANSWER :
Largest 12 bit 2’s
= 111111111111 (binary)
= 2^11 + 2^10 + 2^9 + 2^8 + 2^7 + 2^6 + 2^5 + 2^4 + 2^3 + 2^2 + 2^1 + 1
= 4095
4095 in hexadecimal system :
4095/16 = Q 255 R 15 , take 15 I.e F to unit place.
255/16 = Q15 R 15 , take 15 I.e F to 2nd place (to the left of first place)
15/16 + Q0 R 15 , take 15 I.e. F to 3rd place (to the left of 2nd place)
Hence, 4095 (decimal) is F F F in hexadecimal.
So, the ANSWER is : OxFFF
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