the following 1H NMR spectra are for four compounds each with molecular formula C6H12O2. identify the compounds.
Homework Answers
a. CH3 a show singlet at 2ppm.
Hb shows triplet due to Hc at 4.05ppm. Hc & Hd shows multiplet
at 1.6 & 1.4ppm respectively. CH3e shows triplet due to 2Hd at
0.9ppm.
b.
CH3a show triplet at 2ppm. Hb
shows multiplet at 4.9ppm. it is directly attached to
electronegative Oxygen atom so downfield. CH3c shows doublet due to
Hb at 1.2ppm. 2Hd proton show multiplet at 1.5ppm and CH3e shows
triplet at 0.9ppm.
c.
CH3a show singlet at 2ppm. Hb
shows doublet at 3.8ppm. doublet due to Hc. Hc shows multiplet at
1.9ppm. 2CH3d shows doublet at 0.9ppm. doublet due to Hc.
d.
At 1.98ppm is singlet of CH3b
and at 1.5ppm is singlet of CH3a. All CH3a are equivalent so they
show peak at 1.5ppm.
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