If direction of magnetic feild is inside then current should be folwing in clockwise direction of the loop.
We will use the formula which is shown in uploaded image just go through it first-
Here both 2 horizontal wires will induced the zero magnetic feild at center then-
Br = (4(Pi) * 10-7)(I)(Pi/2) / (4 * pi * 2.301)
then -
B2r = (4(Pi) * 10-7)(I)(Pi/2) / (4 * pi *2* 2.301)
Then-
B3r = (4(Pi) * 10-7)(I)(Pi) / (4 * pi * 3 * 2.301)
And we know that Br + B2r + B3r = 5.933 * 10-7
(4(Pi) * 10-7)(I) / (4 * pi * 2.301) [Pi/2 + Pi/4 + Pi/3] = 5.933 * 10-7
I = 5.933 * 2.301 / [Pi/2 + Pi/4 + Pi/3]
= 13.65 / 3.40
I = 4.01 (Option D)
Thank you !!! Have fun
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