Homework Answers
1) let the alleles be H- dominant results in Huntington`s disease, h- recessive normal
Hh * hh
| H | h | |
| h | Hh ( Huntington`s disease) | hh ( normal) |
| h | Hh ( Huntington`s disease) | hh ( normal) |
chance that the progeny is normal= (number of normal
progeny/total number)
100
= (2/4)100
= 50%
so the answer is 50%.
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