Homework Answers
Terminologies to be remembered
Phenotype: The visible characteristics of an individual which arises after expression of that particular gene responsible for that trait or characteristics.
Genotype: The whole genome or gene set of the individual that are responsible for the phenotype.
Allele: Different variety of same gene. Examples are below
D: Dominant allele
d: recessive allele
Note: D is just a letter to explain the concept where capital letter symbolizes dominant allele and the small letter the recessive gene. It may change as we solve different problems. Also the same letter is used to indicate both alleles.
Homozygous dominant: DD-
genotypically and phenotypically normal
Heterozygous "carrier": Dd- they
are phenotypically normal, but are carriers (genotypically)
Homozygous recessive: dd-
phenotypically and genotypically have the disease or the recessive
allele.
Homozygous Dominant: They are the ones carrying dominant allele or gene which are expressed even if they are coupled with other varieties of allele. (DD)
Homozygous recessive: They are the recessive genes (they can be the cause of the disorder or the disease) which can only be expressed if they are homozygous. (dd)
Heterozygous: As the name suggests the pair formed having one dominant allele and the other recessive gene.
Carrier: Carrier (Heterozygous) is the one that has the recessive allele in the pair which can cause disease but they don't show any phenotypic change due that allele. (Dd)
Genetic Cross: Cross that shows possible offsprings data after breeding of two potential mates. You will understand the cross while the problem will be solved.
Now to solve the problems we would use Genetic cross method.
Question 5.)
Define the genotype of the parents
C: Dominant
c: recessive
CC: Homozygous dominant
Cc: Cystic fibrosis carrier
cc: Cystic Fibrosis
In the question it is mentioned they are both carriers hence they have Cc allele.
There are 4 possible combinations
Answer:
Chance of child being:
1.) 25% Homozygous dominant Genotype: CC
Explanation: There are 25% chances that their child won’t have the disease.
2.) 50% Cystic fibrosis carrier Genotype : Cc
Explanation: There are 50% chances that their child will be a carrier of the disease
3.) 25% Cystic fibrosis Genotype : cc
Explanation: There are 25% chances that their child will have cystic fibrosis
Question 6.)
Define the genotype of the parents
K: Dominant
k: recessive
KK: Homozygous dominant
Kk: PKU carrier
kk: PKU disorder
In the question it is mentioned they are both carriers hence they have Kk allele.
There are 4 possible combinations
Answer
a) be phenotypically normal (KK or
Kk)? 75%
Explanation: This would include both homozygous dominant as well as
heterozygous because in both cases there is no change in the
phenotypes.
So, this would be ¾ = 75%
b) be genotypically normal
(homozygous dominant: KK)? 25%
Explanation: There are 25% chances that their child won’t have the
disorder.
c) be a carrier for PKU (Kk)?
50%
Explanation: There are 50% chances that their child will be a
carrier of the disorder
d) have PKU (kk):
25%
Explanation: There are 25% chances that their child will have PKU
disorder
Add Answer to:
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3. Cystic fibrosis is a recessive genetic disorder that causes too much mucus to build up in the lungs. What rules of genetics do you need to use to solve this problem? a. b. Normal lung functioning (R) is dominant while having cystic fibrosis (r) is recessive. Jessica has cystic fibrosis while Jon is a carrier (a heterozygote). Use a Punnett square to predict the probability that one of their children will have cystic fibrosis. C. Genotypic ratio: Phenotypic Ratio:...
Tony has a sister with cystic fibrosis (CF). Neither of his parents have CF. Tony is expecting a child with Tina. Tina's family history is unknown. (8 points) Below each person in the pedigree, write his or her genotype, or possible genotypes, using C for the normal CF allele and c for the disease-causing CF recessive allele. What is the probability that Tony is a heterozygous carrier for the CF gene? Explain your answer. п CF Tony Tina III If...
Phenylketonuria (PKU) is a recessive disorder that neither Ginny or Harry have. Unfortunately, their son Albus is affected with this condition. Value: 1 What are Ginny and Harry's genotypes? a. Harry is heterozygous and Ginny is homozygous recessive. b. Ginny is heterozygous and Harry is homozygous recessive. c. Harry and Ginny are both heterozygous. d. Harry and Ginny are both homozygous recessive. e. Harry and Ginny are both homozygous dominant. f. Not enough information is available to determine the genotypes...
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