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If a carrier female for cystic fibrosis mates with a normal male (homozygous dominant) what are...

If a carrier female for cystic fibrosis mates with a normal male (homozygous dominant) what are the possible genetic outcomes of their offspring. (Use a punnett square as part of your answer and represent the dominant allele with an “F” and the recessive allele with “f”. Make sure the difference between the alleles is clearly written.) What is the phenotypic ratio of the offspring? What is the genotypic ratio of the offspring? What percentage of offspring will have cystic fibrosis? What percentage of offspring will be carriers for the cystic fibrosis allele?

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Answer #1

Answer:

Ff (carrier female) x FF (normal male)----Parents

F

F

FF (normal)-50%

f

Ff (normal but carrier)-50%

All offspring have the normal phenotype but no one is having cystic fibrosis.

Genotypic ratio = 1:1

The percentage of offspring will have cystic fibrosis = 0%

The percentage of offspring will be carriers for the cystic fibrosis allele= 50%

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