given the following information about the inheritance of characteristics in pea plant answer the questions below
Homework Answers
Answer:
a).
yy genotype produces only one type of gametes, y = 1
RR = 1
Bb = 2
Ss = 2
Ll = 2
The different gametes produced by the female plant = 1*1*2*2*2 =8
b).
Yy x yy = Y_ (1 phenotype) Or Yy & yy (2 genotypes)
Rr x RR = R_ (1 phenotype) Or RR & Rr (2 genotypes)
Bb x Bb = B_ & bb (2 phenotypes) Or BB, Bb & bb (3 genotypes)
SS x Ss = S_ (1 phenotype) Or SS & Ss (2 genotypes)
Ll x Ll =LL, Ll & ll (3 phenotypes) Or LL, Ll & ll (3 genotypes)
Number of different genotypes possible in the F1 offsprings = 2*2*3*2*3 = 72 types of genotypes
c). Number of different phenotypes possible in the F1 offsprings= 1*1*2*1*3=6 types of phenotypes
d).
Green, bitter and smooth = yyB_S_ = ½ * ¾*1 = 3/8*100 = 37.5%
Hairy, medium and sweet = ssLlbb = 0 * ½ * ¼ = 0
Round, bitter and long = R_B_LL = 1*3/4 * ¼ = 3/16 *100 = 18.75%
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