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Sketch a horizontal curve connecting bearings N623243"E to S71045”15"E Label the PC, PI, PT, and bearings....
Part A. The following information is for a proposed horizontal curve in a new subdivision: PI...
Part A. The following information is for a proposed horizontal curve in a new subdivision: PI Station: 12+40.00 R-572.96 feet Deflection angle A-12.30 What is the Station of PT? PI PC PT Part B. An existing highway has a historic site located at the PT of an existing curve with a PI located at Station 80+00, an extemal angle of 65°, and a radius of 1,200 ft. The curve must be relocated, moving the PI to Station 78+00. The external...
The centerline of an existing horizontal curve must be shifted inwards by (50.00 + 4)m. PC...
The
centerline of an existing horizontal curve must be shifted inwards
by (50.00 + 4)m.
PC 4.901.52 Problem 5: (5 points) The centerline of an existing horizontal curve must be shifted inwards by (5.00+y)m (.e., 12.00m). Angle of intersection is 43'00'. Existing curve stationing: PC = 4+901.52; PT, = 5+089.15 Calculate: a. (2pt) the radius and the external distance of the existing curve; b. (1pt) the radius of the new curve; C. (2pt) the stationing of PC, and PT, of...
Determine the SSD for this curve. Calculate the radius of the curve, the length, and stations for PC and PT 3.39 On a r...
Determine the SSD for this curve. Calculate the radius of the
curve, the length, and stations for PC and PT
3.39 On a roadway with two 12-ft lanes, a horizontal curve is designed for 35 mi/h with a 4% superelevation. It is known that Δ-20, The PI of the curve is at station 30 + 00. What is the station of the PT of the curve?
3.39 On a roadway with two 12-ft lanes, a horizontal curve is designed for...
5. For a horizontal curve, A=82'30', the station of the PC is 6+14.00, and terrain conditions...
5. For a horizontal curve, A=82'30', the station of the PC is 6+14.00, and terrain conditions require the minimum radius permitted by the specifications of, 100 ft. (are definition). Calculate (15 points): a. The stationing of PI and PT, and the external (E) and middle ordinate distances (M) and chord length (LC) for this curve. b. Compute sub-deflection angles and sub-chords to stake out this curve. Use quarter-stations 1251 (Note: In the example we solved together in class, we used...
Show all work please. ECC 310 In Class Assignment Curves/Coordinates 10/31/2018 Problem: A horizontal highway curve...
Show all work please.
ECC 310 In Class Assignment Curves/Coordinates 10/31/2018 Problem: A horizontal highway curve has a radius of 567.23 feet, delta angle of 43-24-54, bearing from C to PC of N 22-17-45 W and coordinates at C N 5000.00 E 5000.00 and station of PI- 10+00.00. Draw a sketch of the curve and determine the stationing and coordinates of the PC, PT, Pl and dimensions of all curve components.
For a horizontal curve, the back tangent azimuth is 271 10 37" and the forward tangen azimuth is 51 15'15" and R is...
For a horizontal curve, the back tangent azimuth is 271 10 37" and the forward tangen azimuth is 51 15'15" and R is exactly 3000.00 feet. If the PT Station is 421+ compute the PC, PI and curve midpoint stationing. From a point on the tangen exactly half way between the PC and PT, what is the di 16.98, stance to the midpoint of the curve? Draw a scaled sketch which illustrates the problem. What is the azimuth from the...
HomewUI A circular-horizontal curve to the right has the following characteristics: Δ or l = 8"24...
HomewUI A circular-horizontal curve to the right has the following characteristics: Δ or l = 8"24°00" PI @ Sta. 64+27.46 Dare = 20000" Coordinates of the PI are 1234.56N & 2468.10E R 2864.79 ft The Azimuth of the back tangent is 76 26'30" T = 210.38 ft. (Azimuth from PC to PI) L =420 ft. Draw a sketch and calculate the following: a) The station of the POC b) The coordinates of the PC c) The station of the PT...
Question 5 A circular horizontal curve with radius of 1,430 ft and an intersection angle of...
Question 5 A circular horizontal curve with radius of 1,430 ft and an intersection angle of 14°30' has its point of intersection (PI) at station 572+00. The forward tangent is to be shifted parallel to itself and 10 ft to the left. If the point of curve (PC) remains the same place, what is the radius of the shifted curve? [10] sta 672+00 Pt PC PI' 114 30 10 ft PT PT li 0 not to scale
PI STA = 21 + 3.2 A A-14°46'23" PC N 41°41' 35"E D = 7.49° Figure...
PI STA = 21 + 3.2 A A-14°46'23" PC N 41°41' 35"E D = 7.49° Figure "CC" QUESTION 22 Figure "CC" is a drawing of a horizontal roadway curve. What is the station of the point of tangency (PT)? The answer will be in feet (Not in Station Format) to two(2) decimal place accuracy XXXXX.XX
A horizontal curve is designed for a two-lane road in mountainous terrain. The following data is...
A horizontal curve is designed for a two-lane road in mountainous terrain. The following data is known: Deflection angle: 40 degrees Tangent length: 436.76 feet Station of PI: 2700 10.65 fs = 0.12 e 0.08 Determine the following (a) Design speed= 60 mph (b) Station of the PC 2695+73.89 (c) Station of the PT = 2704+11.64 (d) draw the superelevation attainment detail drawing, show all important stations and lengths. wwwwnO Just Solve part (d)
A horizontal curve is designed for...
Part A. The following information is for a proposed horizontal curve in a new subdivision: PI Station: 12+40.00 R-572.96 feet Deflection angle A-12.30 What is the Station of PT? PI PC PT Part B. An existing highway has a historic site located at the PT of an existing curve with a PI located at Station 80+00, an extemal angle of 65°, and a radius of 1,200 ft. The curve must be relocated, moving the PI to Station 78+00. The external...
The
centerline of an existing horizontal curve must be shifted inwards
by (50.00 + 4)m.
PC 4.901.52 Problem 5: (5 points) The centerline of an existing horizontal curve must be shifted inwards by (5.00+y)m (.e., 12.00m). Angle of intersection is 43'00'. Existing curve stationing: PC = 4+901.52; PT, = 5+089.15 Calculate: a. (2pt) the radius and the external distance of the existing curve; b. (1pt) the radius of the new curve; C. (2pt) the stationing of PC, and PT, of...
Determine the SSD for this curve. Calculate the radius of the
curve, the length, and stations for PC and PT
3.39 On a roadway with two 12-ft lanes, a horizontal curve is designed for 35 mi/h with a 4% superelevation. It is known that Δ-20, The PI of the curve is at station 30 + 00. What is the station of the PT of the curve?
3.39 On a roadway with two 12-ft lanes, a horizontal curve is designed for...
5. For a horizontal curve, A=82'30', the station of the PC is 6+14.00, and terrain conditions require the minimum radius permitted by the specifications of, 100 ft. (are definition). Calculate (15 points): a. The stationing of PI and PT, and the external (E) and middle ordinate distances (M) and chord length (LC) for this curve. b. Compute sub-deflection angles and sub-chords to stake out this curve. Use quarter-stations 1251 (Note: In the example we solved together in class, we used...
Show all work please.
ECC 310 In Class Assignment Curves/Coordinates 10/31/2018 Problem: A horizontal highway curve has a radius of 567.23 feet, delta angle of 43-24-54, bearing from C to PC of N 22-17-45 W and coordinates at C N 5000.00 E 5000.00 and station of PI- 10+00.00. Draw a sketch of the curve and determine the stationing and coordinates of the PC, PT, Pl and dimensions of all curve components.
For a horizontal curve, the back tangent azimuth is 271 10 37" and the forward tangen azimuth is 51 15'15" and R is exactly 3000.00 feet. If the PT Station is 421+ compute the PC, PI and curve midpoint stationing. From a point on the tangen exactly half way between the PC and PT, what is the di 16.98, stance to the midpoint of the curve? Draw a scaled sketch which illustrates the problem. What is the azimuth from the...
HomewUI A circular-horizontal curve to the right has the following characteristics: Δ or l = 8"24°00" PI @ Sta. 64+27.46 Dare = 20000" Coordinates of the PI are 1234.56N & 2468.10E R 2864.79 ft The Azimuth of the back tangent is 76 26'30" T = 210.38 ft. (Azimuth from PC to PI) L =420 ft. Draw a sketch and calculate the following: a) The station of the POC b) The coordinates of the PC c) The station of the PT...
Question 5 A circular horizontal curve with radius of 1,430 ft and an intersection angle of 14°30' has its point of intersection (PI) at station 572+00. The forward tangent is to be shifted parallel to itself and 10 ft to the left. If the point of curve (PC) remains the same place, what is the radius of the shifted curve? [10] sta 672+00 Pt PC PI' 114 30 10 ft PT PT li 0 not to scale
PI STA = 21 + 3.2 A A-14°46'23" PC N 41°41' 35"E D = 7.49° Figure "CC" QUESTION 22 Figure "CC" is a drawing of a horizontal roadway curve. What is the station of the point of tangency (PT)? The answer will be in feet (Not in Station Format) to two(2) decimal place accuracy XXXXX.XX
A horizontal curve is designed for a two-lane road in mountainous terrain. The following data is known: Deflection angle: 40 degrees Tangent length: 436.76 feet Station of PI: 2700 10.65 fs = 0.12 e 0.08 Determine the following (a) Design speed= 60 mph (b) Station of the PC 2695+73.89 (c) Station of the PT = 2704+11.64 (d) draw the superelevation attainment detail drawing, show all important stations and lengths. wwwwnO Just Solve part (d)
A horizontal curve is designed for...
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