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An object of mass m is released from a height of h meters above the ground, as shown in figure below. Determine the ratio of
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Sot: PE at the = mgh P.E at AB - inglo.3/h = 0.3engh. P.E. Converted to K.G. = mgh-o.singh: 0.7 mgh Ratio = 0.35gh = 3 ostini hope it will clear all your doubts please comment if you have any further questions

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