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A car is safely negotiating an unbanked circular turn at a speed of 29 m/s. The...

A car is safely negotiating an unbanked circular turn at a speed of 29 m/s. The road is dry, and the maximum static frictional force acts on the tires. Suddenly a long wet patch in the road decreases the maximum static frictional force to one-sixth of its dry-road value. If the car is to continue safely around the curve, to what speed must the driver slow the car?
m/s

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Answer #1

To make the circular turn, the centripetal force must be equalt to the centrifugal force Here, centripetal acceleration is provided by the force of friction mv but, due wet patch deccreaes the maximum static frictional force to one-sixth of its dry-road value 6 at this condition, umgm solve the v by using the above two expressions 6 7 mv mv 6 ,2 292 v-11.84 m/s

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