Question

Question 8 Not yet answered Marked out of 1.00 P Flag question X, amount won $0 $1 $10 $100 P(x), probability 0.70 0.25 0.04 0.01 Use the table above showing the probability distribution for winning a prize in a game of chance. problems: i. what is the probability of winning at least $10? Answer: It includes the probability of $10 and the probability of $100. P($10)+P($100) = 0.04+0.01 = 0.05 ii. what is the probability of winning less than $100? Answer: It includes the probability of $0 and the probability of $1 and $10. P($0+P($1) + P(10) = 0.70+0.25 +0.04= 0.99 iii. what is the probability of not winning $1? Answer: It includes the probability of winning all other dollars but $10. So, it equals the probability of winning $0, $1, and $100. P($0)+P($1)+P($100) = 0.70+0.25+0.01=0.96 Or, alternatively, we can write using the complement rule or probability: P (not $10) = 1-p($10) = 1-0.04 = 0.96. Question: Use the table above showing the probability distribution for winning a prize in a game of chance. What is the probability of winning less than $10? Select one: O a. 0.04 o b. 0.95 O c. 0.70 O d. 0.99

Answer 1

Question less than $10 =P($o) + P($ 1) Probability of winning = 0.70 +0.25 = 0.95 Answer correct Auswer is (6) Auswer