In a 0.25 M aquous solution of sodium phosphate What is the total concentration of all ions?
Molarity = no. of moles of solute / volume of solution in L
So let us assume the volume of solution be 1 L
Then the number of moles of sodium phosphate in the solution will be 0.25 mol
One mole of Na3PO4 has 4 ions
So 0.25 mol of it will have : 0.25 x 4 = 1.00 mol of ions
Then the molarity of ions = 1.00 /1
= 1 M
In a 0.25 M aquous solution of sodium phosphate What is the total concentration of all...
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I know the answer is A but I don’t know how to get to the
right answer :(
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