Question

please write psedocodes for all of the questions and an algorithm for 2. no coding is required .

FIUJELI 95 PIOL 1. (Geometry: Area of a Pentagon) Write a C# program that prompts the user to enter the length from the center of a pentagon to a vertex and computes the area of the pentagon, as shown in the following figure. The formula for computing the area of a pentagon is Area = 2 , where s is the length of a side the side can be computed using the formula s = 2r sin", wherer is the length from the center of a pentagon to a vertex. Round up two digits after the decimal point. Here is a sample run: Enter the length from the center to a vertex: 5.5 The area of the pentagon is 71.9236 2. (Order three Cities) Write an algorithm and C++ program that prompts the user to enter three cities and displays them in ascending order. Here is a sample run: Enter the first city: Chicago Enter the second city: Los Angeles Enter the third city: Atlanta The three cities in alphabetical order are Atlanta Chicago Los Angeles

Answer 1

At a time we can answer only four questions , so answering first four questions :

Note: for algorithms and code explanations , please find the comments

=====================================================================

//1-----------------------------------------------------------------------------

#include <iostream>

#include <cmath>                    //form math functions like sin() cos()

using namespace std;

int main()

{

    float r;

    cout<<"Enter length of center of pentgon to vertex:";

    cin>>r;

    float s = 2 * r * sin(M_PI/5);  //implementing side formula ; M_PI is a constant defined by cmath library

    float area = (5 * (s*s))/(4 * tan(M_PI/5)); //implementing area formula

    printf("%.2f", area);           //rounding upto 2 digits

    

    return 0;

}

//2-------------------------------------------------------------------------------

//algo

//1)putting 3 cities in an array

//iterating over the array

//starting iteration from 1

//comparing each element with the previous one

//if prev element is lesses than the next one , then swap

#include <iostream>

#include <cmath>

using namespace std;

int main()

{

    string city_container[3];

    cout<<"Enter cisy 1:";

    cin>>city_container[0];

    cout<<"Enter city 2:";

    cin>>city_container[1];

    cout<<"Enter city 3:";

    cin>>city_container[2];

    for (unsigned int i = 1; i < 3; ++i)

    {

        if (city_container[i] <= city_container[i - 1])

        {

            std::swap(city_container[i - 1], city_container[i]);

            i = 0;

        }

    }

    for(int i=0;i<3;i++){

        cout<<city_container[i]<<"\n";

    }

    return 0;

}

//3-----------------------------------------------------------------------

//Store the remainder when the number is divided by 16 in a temporary variable temp. If temp is less than 10, insert (48 + temp) in a character array otherwise if temp is greater than or equals to 10, insert (55 + temp) in the character array.

//Divide the number by 16 now

//Repeat the above two steps until the number is not equal to 0.

//Print the array in reverse order now.

#include <iostream>

#include <cmath>

using namespace std;

int main()

{

    int n;

    cout<<"Enter the number";

    cin>>n;

    // char array to store hexadecimal number

    char hexaDeciNum[100];

      

    // counter for hexadecimal number array

    int i = 0;

    while(n!=0)

    {    

        // temporary variable to store remainder

        int temp  = 0;

          

        // storing remainder in temp variable.

        temp = n % 16;

          

        // check if temp < 10

        if(temp < 10)

        {

            hexaDeciNum[i] = temp + 48;

            i++;

        }

        else

        {

            hexaDeciNum[i] = temp + 55;

            i++;

        }

          

        n = n/16;

    }

    cout<<"The hex value is:";

    // printing hexadecimal number array in reverse order

    for(int j=i-1; j>=0; j--)

        cout << hexaDeciNum[j];

    return 0;

}

//4------------------------------------------------------------------

#include <iostream>

using namespace std;

int main()

{

    

   char x ;

   cout<<"Enter the Character";

   cin>>x;

   switch (x)

   {

       case 'A': printf("Corresponding number  is 2");

               break;

       case 'B': printf("Corresponding number  is 2");

               break;

       case 'C': printf("Corresponding number  is 2");

               break;

       case 'D': printf("Corresponding number  is 3");

               break;

       case 'E': printf("Corresponding number  is 3");

               break;

       case 'F': printf("Corresponding number  is 3");

               break;

       case 'G': printf("Corresponding number  is 4");

               break;

       case 'H': printf("Corresponding number  is 4");

               break;

       case 'I': printf("Corresponding number  is 4");

               break;

       case 'J': printf("Corresponding number  is 5");

               break;

       case 'K': printf("Corresponding number  is 5");

               break;

       case 'L': printf("Corresponding number  is 5");

               break;

       case 'M': printf("Corresponding number  is 6");

               break;

       case 'N': printf("Corresponding number  is 6");

               break;

       case 'O': printf("Corresponding number  is 6");

               break;

       case 'P': printf("Corresponding number  is 7");

               break;

       case 'Q': printf("Corresponding number  is 7");

               break;

       case 'R': printf("Corresponding number  is 7");

               break;

       case 'S': printf("Corresponding number  is 7");

               break;

       case 'T': printf("Corresponding number  is 8");

               break;

       case 'U': printf("Corresponding number  is 8");

               break;

       case 'V': printf("Corresponding number  is 8");

               break;

       case 'W': printf("Corresponding number  is 9");

               break;

       case 'X': printf("Corresponding number  is 9");

               break;

       case 'Y': printf("Corresponding number  is 9");

               break;

       case 'Z': printf("Corresponding number  is 9");

               break;

       default: printf("Invalid option");

                break;   

   }

   return 0;

}