Question

QUESTION I: Write a program that displays the following table: a a^2 a 3 a14 1 1 1 1 2 4 8 16 3 9 27 81 4 16 64 256 QUESTIONUSING PYTHON LANGUAGE.

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Answer #1

1.

print("a\ta^2\t^a^3\ta^4")
for i in range(1,5):
    print(i,"\t",i*i,"\t",i*i*i,"\t",i*i*i*i)

2.

print("approximate value of pie using 4*(1-1/3+1/5-1/7+1/9-1/11) is : ", 4*(1-1/3+1/5-1/7+1/9-1/11) )
print("approximate value of pie using 4*(1-1/3+1/5-1/7+1/9-1/11+1/13-1/15) is : ", 4*(1-1/3+1/5-1/7+1/9-1/11+1/13-1/15) )    

3. Here, it is asked to return reverse order but in example it is shown in the normal order , but I have done coding for both reverse order and normal order

number = int(input("Enter a 6 digit number : "))

new_number = 0
print("numbers in reverse order")
while(number>0):
    remainder = number%10
    number = number//10
    print(remainder)
    new_number = new_number*10+remainder
    
print("numbers in original order")
while(new_number>0):
    remainder = new_number%10
    new_number = new_number//10
    print(remainder)

4.

character = input("Enter a character")
print("UniCode Code for given character is : ",ord(character))

5.

import turtle 
import math
skk = turtle.Turtle()
print(turtle.position())

for i in range(4):
    skk.pencolor("red")
    skk.forward(5)
    skk.right(90)
    skk.forward(5)
    skk.right(90)
    skk.forward(5)
    skk.right(90)
    skk.forward(5)
    skk.right(90)
    skk.pencolor("black")
    skk.forward(100)
    skk.right(90)

# for i in range()
skk.setpos(0,-50)
skk.right(90)
skk.pencolor("blue")
skk.circle(50)
skk.left(90)
skk.forward(100)
skk.pencolor("black")
skk.left(90)
skk.forward(50)
skk.left(135)
j = 0
while (j<35):
  if(j%2 == 0):
    skk.penup()
    skk.forward(4)
  else :
    skk.pendown()
    skk.forward(4)
  j = j+1

turtle.done()

6.

import turtle 
import math

skk = turtle.Turtle()

for i in range(4):
    skk.forward(200)
    skk.right(90)

skk.penup()
skk.forward(5)
skk.right(90)
skk.forward(5)
skk.left(90)
skk.pendown()
skk.pencolor("blue")
for i in range(4):
  skk.forward(80)
  skk.right(90)

skk.penup()
skk.forward(110)
skk.pendown()
skk.pencolor("green")
for i in range(4):
  skk.forward(80)
  skk.right(90)

skk.penup()
skk.right(90)
skk.forward(110)
skk.pendown()
skk.pencolor("yellow")
skk.left(90)
for i in range(4):
  skk.forward(80)
  skk.right(90)

skk.penup()
skk.right(180)
skk.forward(110)
skk.pendown()
skk.pencolor("red")
skk.left(180)
for i in range(4):
  skk.forward(80)
  skk.right(90)

skk.penup()
skk.forward(15)
skk.right(90)
skk.forward(60)
skk.pendown()
skk.fillcolor('red') 
skk.begin_fill()
skk.left(90)
skk.forward(50)
skk.left(120)
skk.forward(50)
skk.left(120)
skk.forward(50)
skk.end_fill()

skk.penup()
skk.left(120)
skk.forward(105)
skk.pendown()
skk.pencolor('yellow')
skk.fillcolor('yellow') 
skk.begin_fill()
skk.forward(60)
skk.left(90)
skk.forward(40)
skk.left(90)
skk.forward(60)
skk.left(90)
skk.forward(40)
skk.left(180)
skk.end_fill()

skk.penup()
skk.forward(130)
skk.right(90)
skk.forward(5)
skk.pendown()
skk.pencolor('green')
skk.fillcolor('green') 
skk.begin_fill()
skk.right(90)
skk.circle(25)
skk.right(90)
skk.end_fill()

skk.penup()
skk.forward(55)
skk.left(90)
skk.forward(30)
skk.pendown()
skk.pencolor('blue')
skk.right(90)
skk.fillcolor('blue') 
skk.begin_fill()
for i in range(4):
    skk.forward(60)
    skk.right(90)
skk.end_fill()

Just a request , Please don`t so much questions at one go , It`s difficult to answer all of them in just 2-3 hrs span . Better break half quantity and ask , it would help us also .
Hope the answers help, If any issue do comment !!

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