SOLUTION :
Distance covered by the object, s = height of the building = 50 ft
Initial velocity of the object, u = 0 ft/s
Final velocity when object reaches the ground = g t = 32.2 t ft/s
Average velocity during interval t = (0 + 32.2 t) / 2 = 16.1 t ft/s
So,
Distance covered, s = average velocity * t
=> 50 = 16.1 t * t
=> t^2 = 50 / 16.1
=> t = sqrt(50 / 16.1)
=> t = time taken by the object to reach the ground = 1.76 sec. (ANSWER).
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