Question

in C++

Description

The purpose of this challenge is to manually manipulate character arrays. This challenge converts text in phone numbers to their equivalent values on a phone keypad.

Requirements

Write a program to decode phone numbers with letters in them.

Create a void function decodetext(char after[], char before[]). This function should be case-insensitive. Do NOT cout in this function.

Declare a char array to hold a maximum of 50 characters.

Ask the user to enter a string. Use cin.getline(char_variable, 50) function call to get the string from the user.

Make sure to ignore (don’t decode) dashes in the string.

Show the decoded phone number

You may need to write other functions to make your code easier. It’s up to you.

Sample Interaction / Output

Enter a phone number: 800-555-HELP
800-555-HELP is actually 800-555-4357

Enter a phone number: ABC-DEF-GHI-JKL-MNO-PQRS-TUV-WXYZ
ABC-DEF-GHI-JKL-MNO-PQRS-TUV-WXYZ is actually 222-333-444-555-666-7777-888-9999

Answer 1

Here is the code for you:

#include <iostream>
using namespace std;
void decodetext(char after[], char before[])
{
    int i;
    for(i = 0; before[i] != '\0'; i++)
    {
       char ch = before[i];
       switch(ch)
       {
          case 'A':
        case 'a':
        case 'B':
   case 'b':
    case 'C':
   case 'c': after[i] = '2'; break;
   case 'D':
        case 'd':
        case 'E':
        case 'e':
        case 'F':
        case 'f': after[i] = '3'; break;
        case 'G':
        case 'g':
        case 'H':
        case 'h':
        case 'I':
        case 'i': after[i] = '4'; break;
        case 'J':
        case 'j':
        case 'K':
        case 'k':
        case 'L':
        case 'l': after[i] = '5'; break;
        case 'M':
        case 'm':
        case 'N':
        case 'n':
        case 'O':
        case 'o': after[i] = '6'; break;
        case 'P':
        case 'p':
        case 'Q':
        case 'q':
        case 'R':
        case 'r':
        case 'S':
        case 's': after[i] = '7'; break;
        case 'T':
        case 't':
        case 'U':
        case 'u':
        case 'V':
        case 'v': after[i] = '8'; break;
        case 'W':
        case 'w':
        case 'X':
        case 'x':
        case 'Y':
        case 'y':
        case 'Z':
        case 'z': after[i] = '9'; break;
        default : after[i] = ch;
    }
}
after[i] = '\0';       
}
int main()
{
    char before[50], after[50];
    cout << "Enter a phone number: ";
    cin.getline(before, 50);
   
    decodetext(after, before);
   
    cout << before << " is actually " << after << endl;
}

And the output screenshot is: