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FULL SCREEN PRINTER VERSION BACK NEXT Question 14 The time to failure (in hours) for a laser in a cytometry machine is modele

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distributed random Variable consider & with the be the parameter exponentially d= 0.00004 100000 Variable with it is a cdf giThe probability that the laser will last at lead 20028 hours? P(x > 20028) - 1-PCX 4 20028) =I- F(20028) =i-fi- (0.00004) (20P(x 2 30 375) = F ( 30 375) = 1 - (0.00004) (30375) 1215 - - = 1- 0.2967100143 = 0.703289(0) P (20028 X < 30375) - F(30375) - F (2002) - 0.703-0.449 = 10.254

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