Homework Answers
here,
the Debroglie wavelength , lamda = 1 * 10^-15 m
let the kinetic energy of the nucleus be KE
the Debroglie wavelength , lamda = 1 * 10^-15 m
lamda = h /sqrt(2 * m * KE)
1 * 10^-15 = 6.634 * 10^-34 /(sqrt(2 * 1.67 * 10^-27 * KE))
solving for KE
KE = 1.31 * 10^-10 J
the kinetic energy of nucleus is 1.31 * 10^-10 J
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