Given that
q1 = 2.40 uC
q2 = 4.35 uC
q3 = - 4.80 uC
(a)
Ey = k*q1/r1^2 + k*q2/r2^2 + k*q3/r3^2
Ey = (8.9*10^9*10^-6) * [ 2.40/(3.50 - 0.75)^2 - 4.80/2.6^2 + 4.35/(2.6 + 0.22)^2 ]
Ey = 1373 J^ N/C
(b)
At x = 3.50 cm
r1 = sqrt(0.75^2 + 3.50^2)
r1 = 3.579 m
r2 = sqrt(0.22^2 + 3.50^2)
r2 = 3.506 m
Ex = k*q1/r1^2 * 3.50/3.579 + k*q2/r2^2 * 3.50/3.506 - k*q3/r3^2
Ex = (8.9*10^3) * [ 2.40/3.579^2 * 3.50/3.579 + 4.35/3.506^2 * 3.50/3.506 - 4.80/3.50^2 ]
Ex = 1287.6 i^ N/C
Ey = - k*q1/r1^2 * 0.75/2.706 + k*q2/r2^2 * 0.22/2.609
Ey = (8.9*10^3) * [ - 2.40/3.579^2 * 0.75/3.579 + 4.35/3.506^2 * 0.22/3.506]
Ey = - 547 j^ N/C
E = 1287.6 i^ - 547 j^ N/C
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