A system of non - linear equations takes a lot of time to solve by hand but can be solved easily by using MATLAB
I explained the solution detailedly by hand and also provided the MATLAB code for your understanding
This is a lengthy answer. I'm hoping that you have some idea about MATLAB. If you don't, don't worry. I explained everything in detail.
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In the above images, inverse of J is calculated in MATLAB. Type inv(J) to get inverse matrix
MATLAB CODE
Editor Window: Type the below code in editor window. Save this code as "NR.m" file for the code to work
function [f,J,inverseJ,x0,xnew]= NR(x,y)
x0=[x;y];
f1 = x^3 - 3*x*y^2 - 2*x + 2;
f2 = 3*x^2*y - y^3 - 2*y;
f=[f1;f2];
J = [3*x^2 - 3*y^2 - 2 -6*x*y; 6*x*y 3*x^2 - 3*y^2 - 2];
inverseJ = inv(J);
xnew = x0 - inverseJ*f;
Iteration 1
Type this in command window and click enter
[f,J,inverseJ,x0,xnew]= NR(1,1)
Output
This will be the output displayed:
f =
-2
0
J =
-2 -6
6 -2
inverseJ =
-0.0500 0.1500
-0.1500 -0.0500
x0 =
1
1
xnew =
0.9000
0.7000
Now again call your function by entering these xnew values as shown below
Iteration 2
Type this in command window
[f,J,inverseJ,x0,xnew]= NR(0.9,0.7)
Output
This will be the output displayed:
f =
-0.3940
-0.0420
J =
-1.0400 -3.7800
3.7800 -1.0400
inverseJ =
-0.0677 0.2459
-0.2459 -0.0677
x0 =
0.9000
0.7000
xnew =
0.8837
0.6003
Similarly, if you repeat the above process for another 3 times, after 5th iteration the values will be converged and required x,y values are obtained as shown below:
Therefore, the required values are (x, y)= (0.8846, 0.5897)
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