Question

4. An average time an atom exists in an excited state is 10-9 s. Upon emitting photon with a wavelength of 600 nm, the atom relaxes back to the ground state. Find the minimal width Av of the emission spectral line measured at this wavelength. (2p) der einen e hoe om te doen

Answer 1

Answers According to heisenberg uncertainity - Principle. DVSC A t 1 E 2h UT uncertainity in time =At = 10ls Time atom exist in ( excited state JE = høU (E = hu) Voir h At A2 = b . o crvekt bers i tot en ar Au= utat = 0.079x109 HZ. width of spectral line = 79 x 106 Hz.