Question

6.5 The voltage across a 4-F capacitor is shown in Fig. 6.45. Find the current waveform. 2 4 6 78 ms)

Answer 1

for two points Solution : The formula for straight line equation (x,y) and (21 Y . (y-yo) = YI YI (x-20). . XX, Here, 4= UCH : . 13t => For ost< 2 ms The Straight line equation of points (0,0) and (2010) (4-0) = 10-0 (2-0) ..2x1030 .y = 10 00 . 2x103 ..y = 5000x VG) = 5000t for ost<2 mg For 2 ms <ts 6 mg Straight line equation of points (2 m, 10) and (Em -d] (4-10) = -10-10 6x1o3-2tiös (al-27103) (9-10). -20 (x-2x103) . L utins (42X10 ) 9-103-5000x+10 y = -5000x + 20 v(t) = - sooot +20.. for 2ms stao mg

for oms&t<.8ms The Straight line equation of pornts (mylo)f(86,0) (y-(-(0)) = 0+10 (X=6*103) 1. 87536xio3 19+0 = 5ooo (x=6783) y +10 = 50000.- 30 ..y = 1500021-40 (t) = sooot-40 .. for onsst.8 ms The votage values are, VGt) scoot. 20-scoot +40+50ot oct<2ms 2mste oms Ġ ms <t<8 ms > current through the The Expression for the capacitor is ict) = c du .. The current through the currerit capacitor of => for osts 2ms P(t)(uxio 6 d (sooot) = (utro6)(5000) = 204103 20mA

- for anset oms PB) = Cotto) (20- 5000+) - Currón) co-sooo) 3 -20110-3 5 - 2010 A for sins te oms '?Ct) = (utro 6) - (- 40+ sooot) (utób) (0+5000) = 20x103 2010 A 2. Current through the capacitor wave form - {(t) man 207 Christ -204