![According to Intel syntax, what memory address is loaded into EAX: (use 8-digit hex format to answer) mov EAX,[EBX * 4 +030]](http://img.homeworklib.com/questions/f64163f0-935f-11ec-93e6-cf54e729440b.png?x-oss-process=image/resize,w_560)
Homework Answers
mov EAX, [EBX * 4 + 030]
value at EBX = 0x000000a1
Here 30 is in decimal
30 in hexadecimal = 0x1E
Address = (0x000000a1)*4 + 0x1E
Address = (0000 0000 0000 0000 0000 0000 1010 0001)<<2 +
0x1E
Address = (0000 0000 0000 0000 0000 0010 1000 0100) + 0x1E
Address = 0x00000284 + 0x1E
Address = 0x000002A2
memory address loaded into EAX = 0x000002A2
Add Answer to:
According to Intel syntax, what memory address is loaded into EAX: (use 8-digit hex format to...
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adds the value 5 to ebx, making EBX = 12, 17, A3, 05.Why is that?ANSWER:varl var2 var3 dd 179 db 0A3h, 017h 012h bca var1 eax. mov add...
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Assembly Code
may I get an explanation for the 3 parts in this question
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please show your steps and note that question 2 has a byte address of 000002 not...
please show your steps and note that question 2 has a
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thanks
Hex Viewer Case Study to be used for questions 1: Review this excerpt from a hex viewer. You can assume that all data shown is in hex. You can assume that two's complement is used to store signed integers with a 16-bit architecture which is byte addressable. Refer to this excerpt to answer the questions below: 000000 8A00 8E00 CFA1 48BF 7900...
Anyone explain to (i), (ii) How can we get the instruction words and R8=?[hex]? (i) instruction...
Anyone explain to (i), (ii)
How can we get the instruction words and R8=?[hex]?
(i) instruction words[hex] is 0x4508, and R8= 0xF002
How can I get that?
(ii) instruction words[hex] is 0x4548 and R8=0x0002
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Assembly Memory Segment Layout (Little Endian) - What does the
"add" instruction do?For example, on the first add instruction (add eax, 3), it moves
the pointer for eax 3 spots to the right.Thus, EAX = 12, 17, A3, 00. (This I understand)But, on the second add instruction (add ebx, 5), it actually
adds the value 5 to ebx, making EBX = 12, 17, A3, 05.Why is that?ANSWER:varl var2 var3 dd 179 db 0A3h, 017h 012h bca var1 eax. mov add...
Assembly Code
may I get an explanation for the 3 parts in this question
Given that . Ar is a label at address 510 EAX has the value 139 . EBX has the value 102 Which bytes in memory will be accessed by the instruction movl $Ar + 38, %ecx Write your answer in the form startByteEndByte with no space in between. If memory is NOT accessed write -1 for your answer. For example, if your answer was bytes 527...
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please show your steps and note that question 2 has a
byte address of 000002 not 000000.
thanks
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Anyone explain to (i), (ii)
How can we get the instruction words and R8=?[hex]?
(i) instruction words[hex] is 0x4508, and R8= 0xF002
How can I get that?
(ii) instruction words[hex] is 0x4548 and R8=0x0002
How can I get that?
Consider the following instructions given in the table below. For each instruction determine its length (in words), the instruction words (in hexadecimal), source operand addressing mode, and the content of register R7 after execution of each instruction. Fill in the empty...
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