What is the address format on a 32‐bit address, 256KB (note the B), 4-way, 8 words per block cache?
What is the address format on a 32‐bit address, 256KB (note the B), 4-way, 8 words...
For a direct-mapped cache with a 32-bit address and 32-bit words, the following address bits are used to access the cache. TAG INDEX OFFSET 31-15 14-8 7-0 a. What is the cache block size (in words)? [13 points] b. How many blocks does the cache have? [12 points]
Design a 256KB (note the B) direct‐mapped data cache that uses a 32‐bit address and 8 words per block. Calculate the following: How many bits are used for the byte offset and why? How many bits are used for the set (index) field? How many bits are used for the tag? What’s the overhead for that cache?
1. A cache holds 64 words where each word is 4 bytes. Assume a 32 bit address. There are four different caches a. A direct-mapped cache with block size = 16 words b. 2-way set-associative cache with block size = 8 words c. 4-way set-associative cache with block size=4 words d. A fully associative cache with block size = 16 words. Complete the table for each cache. Cache a Cache be Cache Cache de 16 Number of bits needed for...
A computer with a 24‐bit address bus has a main memory of size 16 MB and a cache size of 64 KB. The word length is two bytes. a. What is the address format for a direct mapped cache with a line size of 32 words? b. What is the address format for a fully associative cache with a line size of 32 words? c. What is the address format for a 4‐way set associative cache with a line size...
4. Assume that the machine has a 128kB cache with a 32-bit address. Show the address decomposition of a direct-mapped cache (assume 16 bytes per block). Tag Index Offset
Assume a cache with 2048 blocks, a 4-word block size, and a 32-bit address. For each of the following configurations, find the total number of bits for each cache block and the total numbers of bits for the entire cache. a. Direct-mapped b. Two-way set associative c. Four-way set associative d. Fully-associative
Text:
Explain how a 32-bit byte memory address should be divided into
Tag/Index/Offset fields for each of the cache configurations below.
Note: 1KB = 210 bytes. You must explain how many bits to assign to
each field and the ordering of the three fields. You get at most
50% of the credit if you give the length of each field without an
explanation.
1) A fully associative cache with cache block size = 2 words and
cache size = 512KB....
What is the format of an IPv4 address? A 24-bit, dot decimal notation B 32-bit, dot decimal notation 4 octet, separated by colons D 32-bit, separated by colons
Cache of 4096 blocks, a 4-word block size, and a 32-bit address, find the total number of sets and the total number of tag bits for caches that are direct mapped, four-way set associative, and fully associative.
Suppose a computer using set associative cache has 216 words of main memory and a cache of 32 blocks, and each cache block contains 8 words. 3. If this cache is 2-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and word fields? If this cache is 4-way set associative, what is the format of a memory address as seen by the cache?...