Design a 256KB (note the B) direct‐mapped data cache that uses a 32‐bit address and 8 words per block. Calculate the following:
Design a 256KB (note the B) direct‐mapped data cache that uses a 32‐bit address and 8...
Please answer all parts correctly and show your work 3- for a direct mapped cache design with a 32 bit address, the following bits of address are used to access the cache Tag Index Offset 31-10 9-5 4-0 Starting from power on, the following byte addressed cache reference are recorded. Address 0 16 132 232 160 1024 30 140 3100180 2180 d. How many blocks are replaced e. What is the hit ratio f. List final state of the cache,...
For a direct-mapped cache with a 32-bit address and 32-bit words, the following address bits are used to access the cache. TAG INDEX OFFSET 31-15 14-8 7-0 a. What is the cache block size (in words)? [13 points] b. How many blocks does the cache have? [12 points]
For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. Tag Index Offset 31-10 9-4 3-0 How many entries does the cache have?
Consider a 32 KiB (not KB) cache in a system where the processor uses 64-bit words. The system use the byte address of 36-bits. Each cache line (block) stores 256 bits. a) How many bits are used as the byte offset (b)? How many bits are used as the block offset (m)? b) How many index bits are used? How many blocks (lines) are available in the cache? c) Consider the cache being organized as direct-mapped cache. How many bits...
A direct-mapped cache holds 64KB of useful data (not including tag or control bits). Assuming that the block size is 32-byte and the address is 32-bit, find the number of bits needed for tag, index, and byte select fields of the address. Number of bits for offset bits Number of bits for index bits Number of bits for tag bits
Question 17 A direct-mapped cache holds 128KB of useful data (not including tag or control bits). Assuming that the block size is 32-byte and the address is 32-bit, find the number of bits needed for tag, index, and byte select fields of the address. Number of bits for offset bits Number of bits for index bits Number of bits for tag .. bits
For a 16K-byte, direct-mapped cache, suppose the block size is 32 bytes, draw a cache diagram. Indicate the block size, number of blocks, and address field decomposition (block offset, index, and tag bit width) assuming a 32-bit memory address.
12 points A direct mapped cache holds 64KB of useful data (not including tag or control bits). Assuming that the block streis 32-byte and the address is 32-bit, find the number of bits needed for tag index and byte select fields of the address Number of bits for offset bits Number of bits for index bits Number of bits for tag Moving to another question will save this response. Question 17 of 18
Text: Explain how a 32-bit byte memory address should be divided into Tag/Index/Offset fields for each of the cache configurations below. Note: 1KB = 210 bytes. You must explain how many bits to assign to each field and the ordering of the three fields. You get at most 50% of the credit if you give the length of each field without an explanation. 1) A fully associative cache with cache block size = 2 words and cache size = 512KB....
Question 17 12 points Save Answer A direct-mapped cache holds 32KB of useful data (not including tag or control bits). Assuming that the block size is 16-byte and the address is 32-bit, find the number of bits needed for tag, index, and byte select fields of the address. Number of bits for offset bits Number of bits for index bits Number of bits for tag bits