Consider a 32 KiB (not KB) cache in a system where the processor uses 64-bit words....
Consider a 32 KiB (not KB) cache in a system
where the processor uses 64-bit words. The system use the byte
address of 36-bits. Each cache line (block) stores 256 bits.
a) How many bits are used as the byte offset (b)? How many bits are
used as the block offset (m)?
b) How many index bits are used? How many blocks (lines) are available in the cache?
c) Consider the cache being organized as direct-mapped cache. How many bits are required for the tag?
d) How many bits are used in total for this cache?
Homework Answers
a) The cache size is 15 bit. Because 32kib corresponding 32768 byte. It is 2^15 bit . Block offset contain 6 bit(0-5). Byte offset as 2^6 bit.
b) The 8bit cache lines are there. The index bits are 6-13(8bits)
c) The tag bit contain 1 bit
d) The total size of cache is 15 bit.
Add Answer to:
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