For a direct-mapped cache with a 32-bit address and 32-bit words, the following address bits are...

Question

Question

For a direct-mapped cache with a 32-bit address and 32-bit
words, the following address bits are used to access the cache.

TAG	INDEX	OFFSET
31-15	14-8	7-0

a. What is the cache block size (in words)? [13 points]
b. How many blocks does the cache have? [12 points]

Answer 1

Answer #1

a)

offset bits = 0-7 which are 8 (0,1,2,3,4,5,6,7)

Cache line size (or) cache block size = 2^{offset bits} = 2⁸ bytes = 2⁶ words = 64 words

Therefore the cache block size is 64 words.

b)

index bits = 14-8 which are 7 (8,9,10,11,12,13,14)

blocks = 2^{index bits} = 2⁷ lines

Answer 2

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