4. Assume that the machine has a 128kB cache with a 32-bit address. Show the address...
4. Assume that the machine has a 128kB cache with a 32-bit address. Show the address decomposition of a direct-mapped cache (assume 16 bytes per block).
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4. Assume that the machine has a 128kB cache with a 32-bit
address. Show the address...
For a 16K-byte, direct-mapped cache, suppose the block size is 32 bytes, draw a cache diagram....
For a 16K-byte, direct-mapped cache, suppose the block size is 32 bytes, draw a cache diagram. Indicate the block size, number of blocks, and address field decomposition (block offset, index, and tag bit width) assuming a 32-bit memory address.
For a direct-mapped cache with a 32-bit address and 32-bit words, the following address bits are...
For a direct-mapped cache with a 32-bit address and 32-bit words, the following address bits are used to access the cache. TAG INDEX OFFSET 31-15 14-8 7-0 a. What is the cache block size (in words)? [13 points] b. How many blocks does the cache have? [12 points]
Question 3: Consider a 32-bit physical address memory system with block size 16 bytes and a...
Question 3: Consider a 32-bit physical address memory system with block size 16 bytes and a 32 blocks direct mapped cache. The cache is initially empty. The following decimal memory addresses are referenced 1020, 1006, 1022, 5106, 994, and 2019 Map the addresses to cache blocks and indicate whether hit or miss. Note: You must use the hexadecimal approach in solving this question. You must also show the computations of dividing the memory address into tag bits, cache index bits,...
3- for a direct mapped cache design with a 32 bit address, the following bits of address are used...
Please answer all parts correctly and show your work
3- for a direct mapped cache design with a 32 bit address, the following bits of address are used to access the cache Tag Index Offset 31-10 9-5 4-0 Starting from power on, the following byte addressed cache reference are recorded. Address 0 16 132 232 160 1024 30 140 3100180 2180 d. How many blocks are replaced e. What is the hit ratio f. List final state of the cache,...
For a direct-mapped cache design with a 32-bit address, the following bits of the address are...
For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. Tag Index Offset 31-10 9-4 3-0 How many entries does the cache have?
1. A cache holds 64 words where each word is 4 bytes. Assume a 32 bit...
1. A cache holds 64 words where each word is 4 bytes. Assume a 32 bit address. There are four different caches a. A direct-mapped cache with block size = 16 words b. 2-way set-associative cache with block size = 8 words c. 4-way set-associative cache with block size=4 words d. A fully associative cache with block size = 16 words. Complete the table for each cache. Cache a Cache be Cache Cache de 16 Number of bits needed for...
Design a 256KB (note the B) direct‐mapped data cache that uses a 32‐bit address and 8...
Design a 256KB (note the B) direct‐mapped data cache that uses a 32‐bit address and 8 words per block. Calculate the following: How many bits are used for the byte offset and why? How many bits are used for the set (index) field? How many bits are used for the tag? What’s the overhead for that cache?
Question 17 A direct-mapped cache holds 128KB of useful data (not including tag or control bits)....
Question 17 A direct-mapped cache holds 128KB of useful data (not including tag or control bits). Assuming that the block size is 32-byte and the address is 32-bit, find the number of bits needed for tag, index, and byte select fields of the address. Number of bits for offset bits Number of bits for index bits Number of bits for tag .. bits
The physical address of memory on a machine is 32 bits. The machine has a direct...
The physical address of memory on a machine is 32 bits. The machine has a direct mapped cache of size 512 KB with a block size of 8 bytes. What is the size of the tag field in bits? Can you please explain this step by step and what the importance of direct mapped is?
Assume that you have a 32-bit MIPS processor with a direct mapped data cache with the...
Assume that you have a 32-bit MIPS processor with a direct mapped data cache with the capacity 4096 bytes and a block size of 16 bytes. The cache is initially empty (all valid bits are 0). Which sets of the cache have been updated after that the following program has been executed? For each of the sets, specify the set number, the value of the valid bit, and the tag value of the data cache. 1 lui $t0,0x12ff 2 lw...
Question 3: Consider a 32-bit physical address memory system with block size 16 bytes and a 32 blocks direct mapped cache. The cache is initially empty. The following decimal memory addresses are referenced 1020, 1006, 1022, 5106, 994, and 2019 Map the addresses to cache blocks and indicate whether hit or miss. Note: You must use the hexadecimal approach in solving this question. You must also show the computations of dividing the memory address into tag bits, cache index bits,...
Please answer all parts correctly and show your work
3- for a direct mapped cache design with a 32 bit address, the following bits of address are used to access the cache Tag Index Offset 31-10 9-5 4-0 Starting from power on, the following byte addressed cache reference are recorded. Address 0 16 132 232 160 1024 30 140 3100180 2180 d. How many blocks are replaced e. What is the hit ratio f. List final state of the cache,...
1. A cache holds 64 words where each word is 4 bytes. Assume a 32 bit address. There are four different caches a. A direct-mapped cache with block size = 16 words b. 2-way set-associative cache with block size = 8 words c. 4-way set-associative cache with block size=4 words d. A fully associative cache with block size = 16 words. Complete the table for each cache. Cache a Cache be Cache Cache de 16 Number of bits needed for...
Question 17 A direct-mapped cache holds 128KB of useful data (not including tag or control bits). Assuming that the block size is 32-byte and the address is 32-bit, find the number of bits needed for tag, index, and byte select fields of the address. Number of bits for offset bits Number of bits for index bits Number of bits for tag .. bits
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